Answer:
3 grams
Step-by-step explanation:
We are going to take the mass of a bunch of little strips below the triangle "roof." To do this, we must figure out what formula for the mass we'll use, in this case, we'll use:
Mass of strip = denisty * area = (1+x)*y*deltax grams
now, because the "roof" of the triangle contains two different integrals (it completely changes direction), we will use TWO integrals!
**pretend ∈ is the sum symbol
Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral -1 to 0 of (1+x)*3*(x+1) = 3 * integral -1 to 0 of (x^2 + 2x + 1) = 3 * 1/3 = 1
Mass of left part = lim x->0 ∈ (1+x)*y*deltax = inegral 0 to 1 of (1+x)*3*(-x+1) = 3 * integral 0 to 1 of (-x^2 + 1) = 3 * 2/3 = 2
Total mass = mass left + mass right = 1 + 2 = 3 grams
Find area of square: 7^2 = 49
Find radius of circle: 7/2=3.5
find area of circle: 3.5^2*3.14=38.465
Remove area of circle from area of square:
49-38.465=10.535 cm^2
Answer A is the correct one :)
Answer:
Y = [-6 6 6 -6]
Step-by-step explanation:
From the given matrices
If X - 2Y = Z
b - 2c = a ... 1
a -2d = c ...2
4+2a = 16.... 3
a + 2b = b .... 4
From3 ;
2a = 16-4
2a = 12
a = 6
From 4;
a + 2b - b = 0
a+b = 0
a = -b
6 = -b
b = -6
From1;
b - 2c = a
-6 - 2c = 6
-2c = 12
c = -6
also
a - 2d = c
6-2d = -6
-2d = -6-6
-2d = -12
d = 6
Hence the matrices Y = [-6 6 6 -6]