Mr. Verrengia bought some math supplies at the local math depot. He
1 answer:
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<span>2r ≤ 3(2r - 7)
</span><span>2r ≤ 6r - 21
</span><span>21 ≤ 6r - 2r
</span><span>21 ≤ 4r
</span><span>21/4 ≤ r
r</span>
21/4
r 5.25
</span><span>2r ≤ 6r - 21
</span><span>21 ≤ 6r - 2r
</span><span>21 ≤ 4r
</span><span>21/4 ≤ r
r</span>
r
Answer:
Ф =
Step-by-step explanation:
It is a bit difficult to input the work here, so I uploaded an image
- First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
- Then we can combine like terms
- Then we can factor this as a polynomial function
- Then we can set each term equal to zero and solve for Ф
- The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
- The second term tan(Ф) - 1 = 0 has two solutions of
and
so these are the solutions to the problem
