Question

A basketball has a diameter of 9.5 cm. Which of the expressions shows how to determine the volume of air the basketball can hold?

Answer 1

Question is Incomplete; Complete question is given below;

A basketball has a diameter of 9.5 cm. Which of the expressions shows how to determine the volume of air the basketball can hold?

A . 3/4π(4.75)3

B . 3/4π(9.5)3

C . 4/3π(4.75)3

D . 4/3π(9.5)3

Answer:

$C. \frac{4}{3}\pi(4.75)^3 \ cm^3$

Step-by-step explanation:

Given:

Diameter of basket ball = 9.5 cm

So radius is equal to half of the diameter.

radius $(r) = \frac{1}{2}\times 9.5 \ cm = 4.75 \ cm$

Now we need to find the volume of air in the basketball.

Since the shape of basketball is in spherical form hence we will apply formula of volume of Sphere.

Now Volume of air in the Basketball is equal to $\frac{4}{3}$ times π times cube of the radius.

framing in equation form we get;

Volume of air in the Basketball = $\frac{4}{3}\pi(4.75)^3 \ cm^3$

Hence the expression that shows Volume of air in the Basketball  is $\frac{4}{3}\pi(4.75)^3 \ cm^3$