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NNADVOKAT [17]
3 years ago
12

How do you write an exact number when doing the area and circumference of a circle in geometry?

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0
Go 3 decimal points in and round on the 4th

Example
Area=6.8172849286
Simplify 6.817
Circumference= 8.1429716
Simplify 8.143

If this isn't what you mean let me know and I'll help
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What is the rate of change between the points (0,5) and (1,-1)?
erastova [34]

Answer:

Rate of change (slope) = - 6

Step-by-step explanation:

(-1-5)/(1-0) = -6/1 = -6

6 0
2 years ago
Nylan spent $16.72 on 12 ice cream bars. Her cost include $1.24 sales tax how much did each ice cream bar cost before the sales
Ymorist [56]

Answer:


if you use a calculator its easy


16.72 - 1.24 = 15.48

15.48 divided by 12 is 1.29


for sales tax 1.24 divided by 12 is .10


so for each one She spent $1.39


3 0
3 years ago
Read 2 more answers
Explain you can use the whole number expression 248 divided by 4 to check that your answer to exercise 2 is reasonable
Alex17521 [72]
248 ÷ 4 =  62 that is the answer

6 0
3 years ago
Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)
vfiekz [6]

Answer:

Step-by-step explanation:

given a point (x_0,y_0) the equation of a line with slope m that passes through the  given point is

y-y_0 = m(x-x_0) or equivalently

y = mx+(y_0-mx_0).

Recall that a line of the form y=mx+b, the y intercept is b and the x intercept is \frac{-b}{m}.

So, in our case, the y intercept is (y_0-mx_0) and the x  intercept is \frac{mx_0-y_0}{m}.

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph (x_0,\frac{1}{x_0}). Which means that y_0=\frac{1}{x_0}

The slope of the tangent line is given by the derivative of the function evaluated at x_0. Using the properties of derivatives, we get

y' = \frac{-1}{x^2}. So evaluated at x_0 we get m = \frac{-1}{x_0^2}

Replacing the values in our previous findings we get that the y intercept is

(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}

The x intercept is

\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0

The triangle in consideration has height \frac{2}{x_0} and base 2x_0. So the area is

\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0
3 years ago
Drag each label to the correct location on the image.
PSYCHO15rus [73]
1,2,4belong on company sources and 3 should be on external information
6 0
3 years ago
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