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Zolol [24]
3 years ago
6

mridul jogs around a rectangular park of 100m by 80m at the rate of 9km per hour. how much time will he take in jogging 6 rounds

​
Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0

Answer:

14minutes

Step-by-step explanation:

first you need to find the distance which you must find the perimeter P=100+80+100+80

=360 so you multiple it by 6 to get

=2160meters

so you need to convert the meters to kilometers

which is 1000m =1km

what about 2160m you cross multiply

to get 2.16km.

<em>so</em><em> </em><em>th</em><em>e</em><em> </em><em>di</em><em>stance</em><em> </em><em>repre</em><em>sent</em><em> </em><em>D</em><em>=</em><em>2</em><em>.</em><em>1</em><em>6</em><em> </em><em>km</em>

<em> </em><em> </em><em> </em><em>an</em><em>d</em><em> </em><em>spee</em><em>d</em><em> </em><em>represent</em><em> </em><em>S</em><em>=</em><em>9</em><em>k</em><em>m</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>now</em><em> </em><em>yo</em><em>u</em><em> </em><em>nee</em><em>d</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>time</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>T</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>T=D/S

T=2.16km/9km/h

so the km cancels each other

<u>you</u><u> </u><u>get</u><u> </u><u>0</u><u>.</u><u>2</u><u>4</u><u>h</u><u> </u><u> </u><u>for</u><u> </u><u>thi</u><u>s</u><u> </u><u>is</u><u>n't</u><u> </u><u>the</u><u> </u><u>solu</u><u>tion</u><u> </u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><em><u>you</u></em><em> </em><em>k</em><em>now</em><em> </em><em>th</em><em>at</em><em> </em><em>1</em><em> </em><em> </em><em>hour</em><em>=</em><em> </em><em>6</em><em>0</em><em> </em><em>minut</em><em>es</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>what</em><em> </em><em>about</em><em> </em><em>0</em><em>.</em><em>2</em><em>4</em><em>h</em><em> </em><em>you</em><em> </em><em>cr</em><em>oss</em><em> multiply</em>

<em>to</em><em> get</em><em> </em><em>1</em><em>4</em><em>.</em><em>4</em><em> </em><em>so</em><em> </em><em>you</em><em> </em><em>round</em><em> </em><em>it</em><em> </em><em>of</em><em>f</em><em> </em><em>t</em><em>o</em><em> get</em><em> </em><em>1</em><em>4</em><em> </em><em>minut</em><em>es</em>

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Refer to Expression 1 and Expression 2.
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Expression 1 is 25

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Evaluate the function at the indicated values. f(x)= 6x^2+ 5x -12
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Step-by-step explanation:

We need to find the value of the function at the indicated value.

f(x)= 6x^2+ 5x -12

Indicated values are : f(-7), f(0), f(6), f(7)

To find f(-7), put x = -7 in the given function

f(-7)= 6(-7)^2+ 5(-7) -12=247

To find f(0), put x = 0 in the given function

f(0)= 6(0)^2+ 5(0) -12=-12

To find f(6), put x = 6 in the given function

f(6)= 6(6)^2+ 5(6) -12=234

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Acertijo.
Cerrena [4.2K]

La edad de cada uno de los integrantes del acertijo es:

  • <u>Luisa = 3 años </u>
  • <u>Juan = 6 años </u>
  • <u>Carmen = 8 años</u>

<em>Cálculo por medio de ecuaciones y el </em><em>método de igualación</em>.

Haciendo uso de la información brindada en el ejercicio, se procede a formular variables con las cuales se calcularán las ecuaciones, por lo tanto:

  • <em>X = Edad de Luisa</em>
  • <em>Y = Edad de Juan</em>
  • <em>Z = Edad de Carmen</em>

Con el enunciado: <em>"Luisa es 3 años más joven que su hermano Juan"</em> se crea la primera ecuación:

  • 1. Y = X + 3

Con el enunciado: <em>"Su hermana Carmen es 2 años mayor que Juan"</em>, se crea la segunda ecuación:

  • 2. Z = Y + 2

Y con el enunciado: <em>"Juan tiene el doble de edad que Luisa"</em>, se crea la tercera ecuación:

  • 3. X = \frac{Y}{2}

Ahora, utilizando el método de igualación, se reemplaza la <em>tercera ecuación en la primera</em>:

  • Y = X + 3
  • Y = (\frac{Y}{2}) + 3

Y se procede a sumar:

  • Y = (\frac{Y}{2}) + 3
  • Y = \frac{Y+6}{2}

El dividendo se pasa al otro lado de la igualdad a multiplicar:

  • 2Y = Y + 6

Y la variable "Y" que está sumando, se pasa al otro lado de la igualdad a restar:

  • 2Y - Y = 6
  • <u>Y = 6</u>

Con el valor de Y (edad de Juan) <em>se calcula X con la tercera ecuación</em>:

  • X = \frac{Y}{2}
  • X = \frac{6}{2}
  • <u>X = 3</u>

Una vez calculado el valor de X (edad de Luisa), se procede a <em>calcular el valor de Z con la segunda ecuación</em>:

  • Z = Y + 2
  • Z = 6 + 2
  • <u>Z = 8</u>

Por lo tanto, se calcula que <u>la edad de Luisa es 3 años, la edad de Juan es 6 años y la edad de Carmen es 8 años</u>.

Más información sobre ecuaciones:

brainly.com/question/15415929?referrer=searchResults

8 0
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