I need help on this home work

Mathematics

2 answers:

Lady_Fox [76]3 years ago

3 0

Where is the picture at?? I can’t help you

LekaFEV [45]3 years ago

3 0

Answer:

there's nothing

Step-by-step explanation:

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F(x)=2x+3/4x+5 find f(-9)

mylen [45]

$\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

$f(x) = \frac{2x + 3}{4x + 5} \\$

For $f(-9)$ , put " $-9$ " for every value of " $x$ ".

$↬f( - 9) = \frac{2( - 9) + 3}{4( - 9) + 5}\\$

$↬ f(-9) = \frac{ - 18 + 3}{ - 36 + 5} \\$

$↬ f(-9) = \frac{ - 15}{ - 31}\\$

$↬ f(-9)= \frac{15}{31}\\$

$↬f(-9)= 0.48\\$

$\bold{ \green{ \star{ \red{Mystique35}}}}⋆$

6 0

3 years ago

Read 2 more answers

1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg

tamaranim1 [39]

Answer:

The SUV is running at 70 km/h

Step-by-step explanation:

Speed As Rate Of Change

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

$d=\sqrt{x^2+y^2}$

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

$\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}$