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3 years ago

Perpendicular lines AB and CD intersect at point E. If m2AED = x+ 20, what is the value of

Mathematics

1 answer:

Leona [35]3 years ago

5 0

Answer:

x = 70

Step-by-step explanation:

Since the lines are perpendicular then ∠ AED = 90°, thus

x + 20 = 90 ( subtract 20 from both sides )

x = 70

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From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

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3 years ago

For what values of N will the product 3n be less than 50

Butoxors [25]

3n<50

n<50/3

The variable N represents a whole number.
For what values of n will the sum of n+3 be less than 50?

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Maksim231197 [3]

Answer:

Y= 5x + 10

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Step-by-step explanation:

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3 years ago

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Irina-Kira [14]

I believe it is 1.38

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Find the perimeter of the pentagon with vertices M(-2,5), N(2,5), P (5, 3),

wlad13 [49]

The perimeter of the pentagon is approximately 19.6.

<h3>Procedure - Determination of the perimeter of a pentagon</h3><h3 />

In this question we must plot the locations of each vertex on a Cartesian plane to determine the line segments that form the perimeter, whose lengths are determined by Pythagorean theorem and sum the resulting values to find the perimeter.

According to the image attached below, the line segments of the pentagon are MN, NP, PQ, QR and RM. By Pythagorean theorem we have the following lengths:

<h3>Line segment MN</h3><h3 /><h3> $l_{MN} = \sqrt{[2-(-2)]^{2}+(5-5)^{2}}$ </h3><h3> $l_{MN} = 4$ </h3><h3 /><h3>Line segment NP</h3><h3 /><h3> $l_{NP} = \sqrt{(5-2)^{2}+(3-5)^{2}}$ </h3><h3> $l_{NP} = \sqrt{13}$ </h3><h3 /><h3>Line segment PQ</h3><h3 /><h3> $l_{PQ} = \sqrt{(5-5)^{2}+(0-3)^{2}}$ </h3><h3> $l_{PQ} = 3$ </h3><h3 /><h3>Line segment QR</h3><h3 /><h3> $l_{QR} = \sqrt{(3-5)^{2}+(3-0)^{2}}$ </h3><h3> $l_{QR} = \sqrt{13}$ </h3><h3 /><h3>Line segment RM</h3><h3 />

$l_{RM} = \sqrt{(-2-3)^{2}+(5-3)^{2}}$