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vesna_86 [32]
3 years ago
7

What is 3/4divided by3/8​

Mathematics
2 answers:
guapka [62]3 years ago
5 0

Answer:

3/4 divided by 3/8 equals 2

Step-by-step explanation:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

34×83=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

3×84×3=2412

Since 24 divided by 12 equals 2

blondinia [14]3 years ago
3 0

Answer:

2

Step-by-step explanation:

\dfrac{3}{4} \div \dfrac{3}{8} =

= \dfrac{3}{4} \times \dfrac{8}{3}

= \dfrac{3 \times 8}{4 \times 3}

= \dfrac{3 \times 4 \times 2}{4 \times 3}

= \dfrac{4 \times 3 \times 2}{4 \times 3}

= \dfrac{4 \times 3}{4 \times 3} \times \dfrac{2}{1}

= 1 \times 2

= 2

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What is 1.10 fraction of 6000
katrin2010 [14]
In my calculation is divide it 0.00018333333
and if multiply it well be 6600
  
5 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x
BaLLatris [955]

Answer:

The area of the region is 25,351 units^2.

Step-by-step explanation:

The Fundamental Theorem of Calculus:<em> if </em>f<em> is a continuous function on </em>[a,b]<em>, then</em>

                                   \int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) |  {_a^b}

where F is an antiderivative of f.

A function F is an antiderivative of the function f if

                                                    F^{'}(x)=f(x)

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x + 15 and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx

\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx

\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2

3 0
3 years ago
How can I do this, please help me!
sleet_krkn [62]

Answer:

Step-by-step explanation:

3n to the third power+11

n=2

so, 3x2=6, so to simplify take 3x2 three times and make it 9x6=54 then add 11 so it becomes 56+11=65

so the answer is D.

8 0
3 years ago
Read 2 more answers
On the first math test, Keiko answered 19 out of 25 questions correctly. On the second test she got 17 out of 20 correct. On whi
jenyasd209 [6]

Answer:

shegot a better score on the second test

50 is double of 25

75is 3 times 25

100 is 4 times 25

Step-by-step explanation:

19 times 4= 76

17 times 5= 85

7 0
3 years ago
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