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Inessa05 [86]
3 years ago
9

Help I really need help you guys

Mathematics
1 answer:
finlep [7]3 years ago
3 0
HELLO THERE!

(:

This is a problem that looks harder then it seems, First determine the cost of each item he is trying to buy. Then figure out the number of dollars he has to spend. Once you have figured that out you divide the cost into how much he has.

For example.
John has 10 dollars. He wants to buy pencils. Each pencil will cost john 2 Dollars. How many can he buy?

By dividing the cost of the pencils = 2 into the number of dollars he has 10 Divided by 2, we get 5. 

Now it's your turn. Divide the number he has to spend by the price of the items. This will get you your answer! 
Hope this helped!
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Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both insp
Yuliya22 [10]

Complete question is;

Components arriving at a distributor are checked for defects by two different inspectors (each component is checked by both inspectors). The first inspector detects 83% of all defectives that are present, and the second inspector does likewise. At least one inspector does not detect a defect on 34% of all defective components. What is the probability that the following occurs?

(a) A defective component will be detected only by the first inspector?

b) A defective component will be detected by exactly one of the two inspectors?

(c) All three defective components in a batch escape detection by both inspectors (assuming inspections of different components are independent of one another)?

Answer:

A) 0.17

B) 0.34

C) 0

Step-by-step explanation:

a) We are told that the first inspector(A) detects 83% of all defectives that are present, and the second inspector(B) also does the same.

This means that;

P(A) = P(B) = 83% = 0.83

We are also told that at least one inspector does not detect a defect on 34% of all defective components.

Thus;

P(A' ⋃ B') = 0.34

Also, we now that;

P(A ⋂ B) = 1 - P(A' ⋃ B')

P(A ⋂ B) = 1 - 0.34

P(A ⋂ B) = 0.66

Probability that A defective component will be detected only by the first inspector is;

P(A ⋂ B') = P(A) - P(A ⋂ B)

P(A ⋂ B') = 0.83 - 0.66

P(A ⋂ B') = 0.17

B) probability that a defective component will be detected by exactly one of the two inspectors is given as;

P(A ⋂ B') + P(A' ⋂ B) = P(A) + P(B) - 2P(A ⋂ B)

P(A) + P(B) - 2P(A ⋂ B) ; 0.83 + 0.83 - 2(0.66) = 0.34

C) Probability that All three defective components in a batch escape detection by both inspectors is written as;

P(A' ⋃ B') - (P(A ⋂ B') + P(A' ⋂ B))

Plugging in the relevant values, we have;

0.34 - 0.34 = 0

7 0
3 years ago
how many different four letter permutations can be formed using four letters out of the first 12 in the alphabet?
Verizon [17]

Answer:

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

Permutations of four letters from a set of 12 letters. So

P_{(12,4)} = \frac{12!}{(12-4)!} = 11800

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

3 0
3 years ago
If 10% of a number is 44, 5% of the number is
inn [45]

Answer:

22

Step-by-step explanation:

I hope this helps <3

5 0
2 years ago
The answer to question 21 please??
Ad libitum [116K]

Answer:

A = 1/2*(2 + 8)*4 + 1/2*(8 + 7)*2 = 35

35 * 2.25^2 = 177.2 ft² --> Answer c.


5 0
3 years ago
Read 2 more answers
Is -6/11 a irrational number?
Harlamova29_29 [7]

Answer:

No

Step-by-step explanation:

One way to tell if a number is rational is if it can be written as a fraction. Anything that can be written as a fraction of two integers is rational.

-6/11 is a fraction with integer numerators and denominators.

Therefore it is rational.

4 0
3 years ago
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