The average monthly rainfall for 6 months was 28.5 mm. If it had rained 1mm more each month what would the average have been? By
1 answer:
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This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol
Answer:
Quarters: 18.909
Nickels: 49.818
Dimes: 37.818
Somewhere around those numbers.
Step-by-step explanation:
$11.00 total in coins
Nickel = $0.05
Dime = $0.10
Quarter = $0.25
(n*0.05) + (d*0.10) + (q*0.25)
Solve the equation for q.
(n*0.05) + (d*0.10) +( *0.25)
Simplify the expression.
9d + 2n = 440
d - n = -12
Multiply both sides of the equation by -9.
-9d + 9n = 108
9d + 2n = 440
Sum the equations vertically to eliminate at least one variable.
11n = 548
Substitute the given value of n into the equation d - n = -12
Substitute the given value of n into the equation
Finally
d = 37.818
n = 49.818
q = 18.909
Answer:
Step-by-step explanation:
First, we need to isolate by taking it common from both terms on the right:
Now, since we want in terms of the other variables, we can divide the left hand side (A) by whatever is multiplied with
on the right hand side. Then we will have an expression for
. Shown below:
This is the xpression for