The total of 2 buckets of popcorn and 3 boxes of candy would be $23.25
To answer this question you need to form a set of simultaneous equations and solve them. We can do this by saying that a bucket of popcorn = P, and a box of candy = C. Then we can say:
4P + 6C = 46.50
P + C = 9.75
There are then two possible ways to solve; you can either say that C = 9.75 - P using the second equation and then substitute it into the first, or you can multiply the second equation by either 4 or 6 to cancel out P or C.
I’m going to multiply the second equation by 4:
4P + 4C = 39
Now we can subtract this for, the first equation:
4P + 6C = 46.50
4P + 4C = 39
2C = 7.50
C = 3.75
Now we can substitute this value of C into one of the equations to find P:
P + C = 9.75
P + 3.75 = 9.75
P = 6
And now to answer the question, you just multiply P by 2 and C by 3 and add them together, which gives you $23.25
I hope this helps! Let me know if you have any questions :)
Answer: 216
Step-by-step explanation:
So by looking at this equation you should look to see it's key features which will help you graph the equation. the first key feature is the slope, the slope lets you know the angle at which the line will be, the slope in an equation will always be the number multiplied by x ( in this case it'd be 3/4). The second feature is the y intercept, the y intercept is where the equations line crosses the y axis, the y intercept in a graph will always be what is added or subtracted after the x (in this case it'd be 3).
To simplify what I said look at the following:
Slope: 3/4
Y intercept: 3
Hope this helps!
Answer:
(12, 487)
Step-by-step explanation:
y = 3.7x + 442 ----› Eqn. 1
y = 14.4x + 312 ----› Eqn. 2
Substitute y = (3.7x + 442) into eqn. 2.
y = 14.4x + 312 ----› Eqn. 2
3.7x + 442 = 14.4x + 312
Collect like terms
3.7x - 14.4x = -442 + 312
-10.7x = -130
Divide both sides by -10.7
x = 12.1495327
Substitute x = 12.1495327 into eqn. 1.
y = 3.7x + 442 ----› Eqn. 1
y = 3.7(12.1495327) + 442
y = 486.953271
The solution to the system is rounded to the nearest integer:
(12, 487)