√(36g^6) = 6g^3 . . . . a simpler form
It'd be clearer if you'd write: "How many tenths are there in 2 3/5?"
2 3/5 13/5
---------- = ---------- = 26
(1`/10) 1/10
There are 26 tenths in 2 3/5.
Answer:
Well I think it is A because domain is the x values.
Step-by-step explanation:
So when you plug this in your calculator (mine is a ti-84 plus ce) you would hit graph. After it graphs it press Zoom, 0 to center it then press 2nd, trace which pulls up parabola menu's. Press 0 and find the left bound, right bound and then press enter which would give you x values of 2.9375 < t< 6
At the same time I don't know if this is right. I never really excelled at parabolas just trying to help.
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;
PART B
</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;
Answer: multiply the radius times 2 and then multiply the result by 3.14.
Step-by-step explanation:
