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svet-max [94.6K]
3 years ago
5

The term supervised learning refers to the fact that we give the learning algorithm a data set, in which the "right answers" wer

e given. This data set is usually called
Engineering
1 answer:
kenny6666 [7]3 years ago
5 0

Answer: output value

Explanation: Supervised learning is the machine learning task of learning a function that maps an input to an output based on example input-output pairs.

Supervised learning infers a function from labeled training data consisting of a set of training examples.

In supervised learning, each example consists of a pair of an input object (a vector) and a desired output value (the supervisory signal). A supervised learning algorithm analyzes the training data and produces an inferred function, which can be used for mapping new examples. An optimal scenario will allow for the algorithm to correctly determine the class labels for unseen instances. This requires the learning algorithm to generalize from the training data to unseen situations in a "reasonable" way

A wide range of supervised learning algorithms are available, each having its own strengths and weaknesses.

You should now that, there is no single learning algorithm that works better than the other on all supervised learning problems

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A rod is made from two segments: AB is steel and BC is brass. It is fixed at its ends and subjected to a torque of T = 680 N.m.
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Explanation:

see the attached file

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A venturi meter is to be installed in a 63 mm bore section of a piping system to measure the flow rate of water in it. From spac
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Answer:

Throat diameter d_2=28.60 mm

Explanation:

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We know that discharge through venturi meter

 Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

h=x(\dfrac{S_m}{S_w}-1)

S_m=13.6 for Hg and S_w=1 for water.

h=0.235(\dfrac{13.6}{1}-1)

h=2.961 m

Now by putting the all value in

Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}

0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}

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So throat diameter d_2=28.60 mm

     

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