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3 years ago

Una frase de: ama la vida quien___________________________________

Engineering

1 answer:

TEA [102]3 years ago

5 0

Answer:

A phrase from: who loves life

Explanation:

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5. Can you still prepare solutions using available materials at home why

svetoff [14.1K]

Yes, we can by the proper guidance and proper doing. We can create solution by any materials in the house that you need

7 0

3 years ago

A hole of diameter D = 0.25 m is drilled through the center of a solid block of square cross section with w = 1 m on a side. The

attashe74 [19]

Answer:

$q=4.013\:\:kW\\\\T_1=278.91\:\:^{\circ}C\\\\T_2=275.82\:\:^{\circ}C$

Explanation:

$R_{conv,1}=(h_1\pi D_1L)^{-1}=(50*0.25*2)^{-1}=0.01273\:\:K/W\\\\R_{conv,2}=(h^2*4wL)^{-1}=(4*4*1)^{-1}=0.0625\:\:K/W\\\\R_{cond(2D)}=(Sk)^{-1}=(8.59*150)^{-1}=0.00078\:\:K/W$

So, heat rate can be calculated as follows:

$q=\frac{T_{\infty,1}-T_{\infty,2}}{R_{conv,1}+R_{conv,2}+R_{cond(2D)}} =\frac{330-25}{0.076} =4.013\:\:kW$

Surface temperatures can be calculated as follows:

$T_1=T_{\infty,1}-qR_{conv,1}=330-51.09=278.91\:\:^{\circ}C\\\\T_2=T_{\infty,2}+qR_{conv,2}=25+250.82=275.82\:\:^{\circ}C$

6 0

4 years ago

A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields

vampirchik [111]

Answer:

The percent elongation in the length of the specimen is 42%

Explanation:

Given that:

The gage length of the original test specimen $L_o$ = 50 mm

The final gage length $L_f$ = 71 mm

The area = 206 mm²

maximum load = 162,699 N

To determine the percent elongation in %, we use the formula:

$\%EL = \dfrac{L_f-L_o}{L_o}\times 100$

$\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100$

$\%EL = \dfrac{21 mm}{50 \ mm}\times 100$

$\%EL = 0.42 \times 100$

$\mathbf{\%EL = 42 \%}$

The percent elongation in the length of the specimen is 42%

4 0

4 years ago

What is the first step in the Design Process *

Gennadij [26K]

Answer:

Define the problem

I hope this helps!

Explanation:

The problem must be know before you can develop and solution, generate concepts, or construct and test a prototype

8 0

3 years ago

A simple undamped spring-mass system is set into motion from rest by giving it an initial velocity of 100 mm/s. It oscillates wi

____ [38]

Answer:

f=1.59 Hz

Explanation:

Given that

Simple undamped system means ,system does not consists any damper.If system consists damper then it is damped spring mass system.

Velocity = 100 mm/s

Maximum amplitude = 10 mm

We know that for a simple undamped system spring mass system

$V_{max}=\omega A$

now by putting the values

$V_{max}=\omega A$

100 = ω x 10

ω = 10 rad/s

We also know that

ω=2π f

10 = 2 x π x f

f=1.59 Hz

So the natural frequency will be f=1.59 Hz.

6 0

4 years ago