Which word has line symmetry, DAD, ODE, or HOME

Reika [66]

For range it’s highest number minus lowest number so:
28 - 21 = 7

For median it’s the middle number:
Since there’s two we add them and dive it by two so:
25 + 24 = 49 dived by 2 = 24.5

For mode it’s most occurring number in this case :
All of them appear twice so none of them are the mode

7 0

4 years ago

Solve the system using the substitution method: 3x + 5y = -10 X - 5y =-10

inn [45]

Answer:

Point Form:

(−5,1)

Equation Form:

x=−5, y=1

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

1. x=5y−10

2. 20y−30=−10

3. y=1

4. x=−5

4 0

3 years ago

What is the graph of

Veseljchak [2.6K]

Answer: a coordinate grid

5 0

4 years ago

A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover

victus00 [196]

Answer:

Answer:

a. Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

b) Ending Inventory: Matrix D:

Hard Soft Plastic

San Francisco 400 4,800 3,000

Los Angeles 1,600 7,800 3,000

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

Hard Soft Plastic

San Francisco 1,000 3,000 6,000

Los Angeles 1,000 6,000 3,000

Sales in January: Matrix B

Hard Soft Plastic

San Francisco 700 1,200 2,000

Los Angeles 400 200 500

Restocking: Matrix C

Hard Soft Plastic

San Francisco 600 1,500 1,500

Los Angeles 500 500 500

Total Sales over the first 6 months =

Matrix B * 6 = Matrix B6

Sales in January: Matrix B

Hard Soft Plastic

San Francisco 700 1,200 2,000

Los Angeles 400 200 500

* 6

=

Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

Matrix C6 = Matrix C * 6

=

Restocking: Matrix C6

Hard Soft Plastic

San Francisco 3,600 9,000 9,000

Los Angeles 3,000 3,000 3,000

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

Hard Soft Plastic

San Francisco 1,000 3,000 6,000

Los Angeles 1,000 6,000 3,000

+

Restocking: Matrix C6

Hard Soft Plastic

San Francisco 3,600 9,000 9,000

Los Angeles 3,000 3,000 3,000

-

Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

Ending Inventory: Matrix D:

Hard Soft Plastic

San Francisco 400 4,800 3,000

Los Angeles 1,600 7,800 3,000

3 0

3 years ago

Taylor surveys students in one grade level who own at least one pet. She finds that 50% of the students surveyed own 2 pets, 3 s

Llana [10]

First, we need to work out the total number of students who were being surveyed.

We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population

That means total number of students being surveyed is 13+13=26 students

Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13

The probability distribution is shown in the table below. Let $x$ be the number of pets and $P(X=x)$ is the probability of owning the number of pets

3 0

4 years ago

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