2X+4=20+5XA)1/2 B)-1/2 C)2 D)-2
1 answer:
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<u>Answer:</u>
The older repear will harvest in 6 hrs
<u>Explanation:</u>
Given a field can be harvested in 1 hr with 2 reapers
Consider the total field to be 1
Let x be the time of older’s reaper
The field can be harvested in 1.2 hr with newer reaper alone
Older’s time of harvesting = per hour
Newer’s time of harvesting = per hour
Total (Older+Newer) = 1 = }
1.2 + x = 1.2x
1.2 = 0.2x
x = 6
Therefore, older repear will harvest in 6 hrs