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3 years ago

Given that g(y) = y2 - 1, find g(a - 1).Give your answer in its simplest form.

Mathematics

1 answer:

AlekseyPX3 years ago

8 0

Answer:

a^2 - 2a.

Step-by-step explanation:

Replace the y in g(y) by a - 1 and simplify.

g(a-1) = (a - 1)^2 - 1

= a^2 - 2a + 1 - 1

= a^2 - 2a.

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PLLLLEEEEEEAAASSSSSSSSEEEE

mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

Therefore, any of these lines are not perpendicular to each other.

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Step-by-step explanation:

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2 years ago

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"what is the binary equivalent of the decimal value 97?"

AleksandrR [38]

01100001 = 97 64+32+1=97 (if the leading bit is 0 it's usually not shown)
very easy
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Bit 1 Value 128
Bit 2 value 64
Bit 3 value 32
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Bit 5 value 8
Bit 6 value 4
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3 years ago

Given that g(y) = y2 - 1, find g(a - 1).Give your answer in its simplest form.​

Given that g(y) = y2 - 1, find g(a - 1).Give your answer in its simplest form.