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GarryVolchara [31]
3 years ago
5

Keisha solved the following equation:

Mathematics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

No 4 I think not to sure tho

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The sixth-grade art students are making a mosaic using tiles in the shape of right triangles. Each tile has leg measures of 3 ce
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The area of the mosaic would be 1500 cm^2
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3 years ago
There are 10 red marbles and 20 green marbles in a bag. Colleen says the ratio of red marbles to green marbels is 19 to 20. Frit
nadezda [96]
Fritz is correct, in that the ratio is 1:2

Think of the ratio as a division

10:20 = 10/20

When you divide 10 with 20, you will get a decimal (or simplified fraction)

10/20 = 0.5

0.5 = 50 percent, or 1:2


Fritz is correct, in that 1:2 is the ratio

hope this helps
6 0
3 years ago
Read 2 more answers
Which are the better statistics to use to compare the penguin heights?
frozen [14]

Answer:

The correct options are A and B.

Step-by-step explanation:

The Penguin Heights at City view Zoo (in cm) is:

S = {35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45}

Compute the mean and median of the data:

\text{Mean}=\frac{1}{n}\sum X\\\\=\frac{1}{11}\times [35+36+37+38+39+40+41+42+43+44+45]\\\\=40

\text{Median}=[\frac{n+1}{2}]^{th}obs.\\\\=[\frac{11+1}{2}]^{th}obs.\\\\=6^{th}obs.\\\\=40

The mean and median are same.

Tis implies that the height of penguins are normally distributed.

So, either the mean or median could be the best measure of center.

Standard deviation is one of the measure of dispersion or spread of a dataset from the average value of the dataset. The standard deviation measures the absolute variability of the distribution of values.

The higher the spread or variability in the data set, the greater is the standard deviation value and thus greater will be the magnitude of the deviance of the value from their average.

Thus, the correct options are A and B.

3 0
3 years ago
The 7 in which number represents a value of 0.7
Drupady [299]

Answer:

The answer is C

Step-by-step explanation:

good job on quiz i got a 15/15 but keep up 3´5

6 0
2 years ago
Read 2 more answers
Working for a car company, you have been assigned to find the average miles per gallon (mpg) for acertain model of car. you take
Orlov [11]

Answer:

a) The 95% confidence interval for the mean mpg, for the certain model of car is (23.3, 30.1). This means that we are 95% sure that the true mean mpg of the model of the car is between 23.3 mpg and 30.1 mpg.

b) Increasing the confidence level, the value of T would increase, thus increasing the margin of error and making the interval wider.

c) 37 cars would have to be sampled.

Step-by-step explanation:

Question a:

We have the sample standard deviation, and thus, the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.1448

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.1448\frac{6.2}{\sqrt{15}} = 3.4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 26.7 - 3.4 = 23.3 mpg.

The upper end of the interval is the sample mean added to M. So it is 26.7 + 3.4 = 30.1 mpg.

The 95% confidence interval for the mean mpg, for the certain model of car is (23.3, 30.1). This means that we are 95% sure that the true mean mpg of the model of the car is between 23.3 mpg and 30.1 mpg.

b. What would happen to the interval if you increased the confidence level from 95% to 99%? Explain

Increasing the confidence level, the value of T would increase, thus increasing the margin of error and making the interval wider.

c. The lead engineer is not happy with the interval you constructed and would like to keep the width of the whole interval to be less than 4 mpg wide. How many cars would you have to sample to create the interval the engineer is requesting?

Width is twice the margin of error, so a margin of error of 2 would be need. To solve this, we have to consider the population standard deviation as \sigma = 6.2, and then use the z-distribution.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many cars would you have to sample to create the interval the engineer is requesting?

This is n for which M = 2. So

M = z\frac{\sigma}{\sqrt{n}}

2 = 1.96\frac{6.2}{\sqrt{n}}

2\sqrt{n} = 1.96*6.2

\sqrt{n} = \frac{1.96*6.2}{2}

(\sqrt{n})^2 = (\frac{1.96*6.2}{2})^2

n = 36.9

Rounding up:

37 cars would have to be sampled.

8 0
3 years ago
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