Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
24° and 66°
Step-by-step explanation:
Angle 1 = x
Angle 2 = x + 42°
x + x + 42° = 90°
Subtract 42° from both sides and add
2x = 48°
Divide by 2
x = 24°
24° and 66°
Hope this was useful to you!
Answer:
8.80 if it's the 40°/.
2.20 if it's the 10°/. processing fee
13.20 for how much he paid
Answer: c = 2h + 15
Step-by-step explanation: Each house (h) adds 2 cats. We represent that with 2h. Then we add the constant 15 on the ground as +15.