Answer: 3^12 x 7^9 = 2.144556126 x 10^13
Step-by-step explanation:
3^12 = 531,441
7^9 = 40,353,607
531,441 x 40,353,607 = 2.144556126 x 10^13
The average speed of the rocket from 3 to 4 seconds after launch is: -40 ft/s
Given the equation as a model, h(t) =–16t² + 72t.
Average speed from 3 to 4 seconds =
<em>Find h(4):</em>
h(t) =–16t² + 72t
- Substitute 4 for t in the equation h(t) =–16t² + 72t
h(4) = -16(4)² + 72(4)
h(4) = -256 + 288
h(4) = 32
<em>Find h(3):</em>
h(t) = -16t² + 72t
- Substitute 3 for t in the equation h(t) =–16t² + 72t
h(3) = -16(3)² + 72(3)
h(3) = -144 + 216
h(3) = 72
Plug in the value into :
average speed from 3 to 4 secs =
Therefore, the average speed of the rocket from 3 to 4 seconds after launch is: -40 ft/s
Learn more about average rate of change on:
brainly.com/question/11627203
Answer:
A.105°
Step-by-step explanation:
Angle at W and V are equal and the angles at T and U are also equal
Hence taking angles at T and U...so as to calculate the value of x
5x + 15 = 3x + 21
5x - 3x = 21 - 15
2x = 6.....hence, x = 3
Then for the angle of VXU;
All angles in a triangle add up to 180°
15(3) + 3(3) + 21 = 75°...then subtract from 180°..so as to obtain angle at VXU
180 - 75 = 105°
Step-by-step explanation:
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Answer:
This is the concept of geometry, we are required to calculate for the length of the sides of the rhombus; we know that a rhombus is a compressed square, this implies that all the sides are equal;
If one of the angles is 110° the other angle will be:
180-110=70°
thus using the cosine rule we can find the side lengths as follows;
c^2=a^2+b^2-2ac Cos C
thus
let side a=b=x in
shorter diagonal=c=4 in
C=70°
substituting this into the formula we get:
4^2=x^2+x^2-2*x*x Cos 70
4^2=2x^2-2x^2(0.3420)
16=2x^2-2x^2(0.3420)
dividing through by 2 we get;
8=x^2-0.3420x^2
8=0.6580x^2
x^2=12.15843
getting the square root of both sides get:
x=sqrt(12.15843
x=3.4869)
x=3.5 (1 d.p)
the length of the sides is 3.5