As per the given statement: Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month.

⇒ $\text{Total length of the trip to and fro from work last month} = 14.6 km$

Also, it is given that Jeremiah worked 18 days.

then;

$\text{Total distance he ride his bike} = 14.6 \times 18 = \frac{146}{10} \times 18 = \frac{146 \times 18}{10} = \frac{2628}{10}$

Simplify:

$\text{Total distance he ride his bike} = 262.8 km$

Therefore, 262.8 km did he rode his bike to and from work last month

8 0

4 years ago

 (6 pts) The average age of CEOs is 56 years. Assume the variable is normally distributed. If the SD is four years, find the pr

Alenkinab [10]

Answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is 0.334.

Step-by-step explanation:

We have a normal distribution with mean=56 years and s.d.=4 years.

We have to calculate the probability that a randomly selected CEO have an age between 50 and 55.

We have to calculate the z-value for 50 and 55.

For x=50:

$z=\frac{x-\mu}{\sigma}=\frac{50-56}{4}=\frac{-6}{4}= -1.5$

For x=55:

$z=\frac{x-\mu}{\sigma}=\frac{55-56}{4}=\frac{-1}{4}=-0.25$

The probability of being between 50 and 55 years is equal to the difference between the probability of being under 55 years and the probability of being under 50 years:

$P(50$

5 0

4 years ago

Lily babysits on the weekends. She

Anastaziya [24]

Answer: She babysat 7 hours

Step-by-step explanation:if you take the knowledge you have; she charges 6$ per hour. and lily mad 42$ you can divide 42 by 6 to get the answer of 7

8 0

3 years ago

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