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GaryK [48]
3 years ago
13

At the beginning of the day, it was -14 degrees. Throughout the day, the temperature increased 16 degrees. What was the temperat

ure (in degrees) at the end of the day? At the beginning of the day, it was -14 degrees. Throughout the day, the temperature increased 16 degrees. What was the temperature (in degrees) at the end of the day?
Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

The temperature at the end of the day is 2 degrees

Step-by-step explanation:

Here, we are interested in calculating the temperature at the end of the day.

In the question, we are told that at the beginning of the day, temperature was -14 degrees.

But throughout the day, the temperature increased by 16 degrees;

Thus, the temperature at the end of the day = -14 degrees + 16 degrees = 2 degrees

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Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor
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Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

<u>Solution:</u>

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is \frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }

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\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}

On cross-multiplication we get,

\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}

\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}

On cross multiplication ,we get

\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}

<em><u>using quadratic formula:-</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

x=\frac{12 \pm \sqrt{144-40}}{2}

\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

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The amount of interest earned every year with simple interest is constant. <br>true or false​
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