HELPPP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

BRUH WHY DO YOU GUYS NOT ANSWER MY QUESTIONS DO YOU NOT KNOW HOW IMPORTANT THIS IS?!

iren2701 [21]

Answer:

the two graph depicting proportional relationships are the top right and bottom left graphs

hope this helps and btw maybe make ur questions worth more points and dont make titles like this one lol also if its worth like 15 or more points put "__ POINTS"

have a great day!

8 0

3 years ago

I need help w geometry

aniked [119]

What changes might help "Happiness is a charming Charlie Brown at orlando rep" to take on the general purpose of "You're a good man, Charlie Brown?

8 0

3 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size n = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size n = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

3 years ago

Please help thanks in advance also best answer get's brainlest

Neko [114]

Answer:

angle t is 55 degrees

Step-by-step explanation:

Here's my work:

Isoscelese means two of the same length sides. A triangle is 180 degrees. 180-70=110

110/2=55 (two because those are the two angles associated with the equal sides)

5 0

3 years ago

If f(x)=x^2-11, for what values of z is f(x) < 25?

GuDViN [60]

Answer:

D

Step-by-step explanation:

f(x) < 25

x² - 11 < 25

x² < 36

-6 < x < 6

5 0

3 years ago