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Try this option (it is not the only way):
the points (0;0) and (2;2) belong to the curve. Using the coordinates of these points it is possible to calculate the equation.
the points (0;0) and (2;2) belong to the curve. Using the coordinates of these points it is possible to calculate the equation.
Equation of a tangent line of a curve is:
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)=
(Derivation)
f´(x0)=
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =
y- y0 = f´ (x0) (x - x0 ). In this case: x0=1, y0=1
f´(x)=
f´(x0)=
y - 1 = 1/2 ( x - 1 )
y - 1 = 1/2 x - 1/2
y = 1/2 x - 1/2 + 1
y =