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pishuonlain [190]
3 years ago
9

Marsha has some math exercises to do for homework. She did one half during study period and two thirds of those remaining while

waiting for a friend after school. He had three to finish at home that evening. How many exercises did she have for homework?
Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Answer: She has 1 5/6 exercises for homework.

Step-by-step explanation:

1/2 + 2/3 = 1 1/6

2 * 3 = 6 3 * 2 = 6

1 * 3 = 3 2 * 2 = 4

4 + 3/ 3 + 3

7/6 = 1 1/6

So, she finished 1 1/6 of her problems.

3 - 1 1/6 = 1 5/6

3 - 1 = 2

2 - 1/6 = 1 5/6

pshichka [43]3 years ago
3 0

Answer:  18

Step-by-step explanation:

Let x represents the number of exercises she had for homework.

Then, the expression for the number of exercises she did during study period =\dfrac{x}{2}

Remaining exercise = x-\dfrac{x}{2}=\dfrac{x}{2}

The number of exercises she did while waiting for a friend after school=\dfrac{2}{3}\times\dfrac{x}{2}=\dfrac{x}{3}

Also, she had three to finish at home that evening.

Then, we have

x=\dfrac{x}{2}+\dfrac{x}{3}+3\\\\\Rightarrow\ x-\dfrac{x}{2}-\dfrac{x}{3}=3\\\\\Rightarrow\dfrac{6x-3x-2x}{6}=3\\\\\Rightarrow\dfrac{x}{6}=3\\\\\Rightarrow\ x=6\times3=18

Hence, she had 18 exercises for homework.

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Answer:

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Step-by-step explanation:

The volume of a pyramid is one third the height times the area of the base.

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The base is a square, so the area is the width times length.

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Problem is, we don't know the height, only the slant length.  But we can use this to find the height.

If we cut a cross section down the middle of the pyramid, we get an isosceles triangle.  The base of the triangle is 24, and the legs are 37.

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