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mina [271]
3 years ago
9

1. Write the equation that models the height of the roller coaster.

Mathematics
2 answers:
umka2103 [35]3 years ago
8 0

Answer: Answer:

a.)x² + y² = 900

b.)y = √900 - x²

Step-by-step explanation:

P.S - The exact equation is as follows :

As given,

The shape of the roller coaster is a half of a circle. Center the circle at the origin and assume the highest point on this leg of the roller coaster is 30 feet above the ground.

a.)

Equation of circle be x² + y² = r²

As given , leg of the roller coaster is 30 feet above the ground.

⇒ r = 30

⇒x² + y² = 30²

⇒x² + y² = 900

∴ we get

Equation of height of Roller coaster - x² + y² = 900

b.)

As we have,  x² + y² = 900

⇒y² = 900 - x²

⇒y = √900 - x²

Step-by-step explanation:

Basile [38]3 years ago
5 0

Answer:

im on this right now and im so comfused

Step-by-step explanation:

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Select the correct answer.
Alex787 [66]

Answer:

A) y=3/2x-12

Step-by-step explanation:

Slope intercept formula is y=mx+b

mx is the slope.

B is the y intercept

8 0
3 years ago
Read 2 more answers
It takes Dwight 1 1/3 hours to run the sunshine trail. Mike 3 1/5 hours to walk the same trail. How many times as long does it t
Anit [1.1K]

For this case we convert the mixed numbers to fractions:

Dwight:1 \frac {1} {3} = \frac {3 * 1 + 1} {3} = \frac {4} {3} = 1.33

Mike:3 \frac {1} {5} = \frac {5 * 3 + 1} {5} = \frac {16} {5} = 3.2

It is observed, that in fact, Mike takes more time to travel the road.

We subtract to know how much more time it takes Mike:

\frac {16} {5} - \frac {4} {3} = \frac {48-20} {15} = \frac {28} {15}

So, Mike takes \frac {28} {15} hours more than Dwight to walk the road.

Answer:

Mike takes\frac {28} {15}hours longer than Dwight to walk the road.

7 0
3 years ago
Solve system by elimination <br> -5x-10y=-20<br> 10x+10y=0
bekas [8.4K]

Answer:

(-4,4)

Step-by-step explanation:

-5x-10y=-20

10x+10y=0

divide both sides by 2

-5x-10y=-20

5x+5y=0

that makes

-5y=-20

divide both sides by -5

y=4

now substitute 4 for y

10x+10 x 4=0

multiply

10x+40=0

subtract

10x=-40

divide

x=-4

7 0
3 years ago
Read 2 more answers
Given vectors A (2,-1,5), B (4,3,-2) &amp; C (5,4,0), find:?
MrRissso [65]
A) 4a - 3b + 2c

4(2, -1, 5) - 3(4, 3 , -2) + 2(5, 4, 0) = (8, -4, 20) - (12, 9, - 6) + (10, 8, 0) =

= (8 - 12 + 10 , -4 - 9 + 8 , 20 + 6 + 0) = (6, - 5, 26)

Answer: (6, - 5, 26)

b) magnitude of vector b

\sqrt{4^2+3^2+(-2)^2} = \sqrt{16+9+4} = \sqrt{29} ~ 5.4

c) vector of length 7 parallel to vector c

=> m(5,4,0) = (5m,4m,0)

=>    \sqrt{(5m)^2+(4m)^2+0}= \sqrt{25m^2+16m^2}= \sqrt{41m^2}=m \sqrt{41}=7

=> m = 7 / √41 ≈ 1.093

=> 1.093 (5, 4, 0) = (5.465 , 4.372, 0)

Answer: (5.465 , 4.372 , 0)
7 0
3 years ago
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maksim [4K]

Answer:

lala lala 4 yes did that work

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2 years ago
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