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3 years ago

Write an algebraic expression that models the word phrase "the product of 8 and the sum of a number X and 3"

Mathematics

1 answer:

Leya [2.2K]3 years ago

4 0

The answer is d.
8(x+3)

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What is the effect in the time required to solve a problem when you double the size of the input from n to 2n, assuming the numb

kobusy [5.1K]

Answer:

Go to this site

https://www.slader.com/discussion/question/what-is-the-effect-in-the-time-required-to-solve-a-problem-when-you-double-the-size-of-the-input-fro/

there should the your answer

Step-by-step explanation:

3 0

3 years ago

I need to know how to solve the problem:<br><br><br>3/2x+1/5x=11/6x-2/15

Schach [20]

3/2x + 1/5x = 11/6x - 2/15....to get rid of fractions, multiply by common denominator, which is 30.

45x + 6x = 55x - 4
51x = 55x - 4
51x - 55x = -4
-4x = -4
x = -4/-4
x = 1

4 0

3 years ago

Read 2 more answers

Point M is located at (-6,6).<br> What is located 5 units from point M?

timurjin [86]

Do you have a picture? Normally this kind of problem features a graph with other points included. -1,6? -6,1? -11,6? -6,11?

6 0

2 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago

How would I do this?

Georgia [21]

Work shown above! Answer would be 110 degrees!

3 0

3 years ago