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Alisiya [41]
3 years ago
9

Write an algebraic expression that models the word phrase "the product of 8 and the sum of a number X and 3"

Mathematics
1 answer:
Leya [2.2K]3 years ago
4 0
The answer is d.
8(x+3)
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What is the effect in the time required to solve a problem when you double the size of the input from n to 2n, assuming the numb
kobusy [5.1K]

Answer:

Go to this site

https://www.slader.com/discussion/question/what-is-the-effect-in-the-time-required-to-solve-a-problem-when-you-double-the-size-of-the-input-fro/

there should the your answer

Step-by-step explanation:

3 0
3 years ago
I need to know how to solve the problem:<br><br><br>3/2x+1/5x=11/6x-2/15
Schach [20]
3/2x + 1/5x = 11/6x - 2/15....to get rid of fractions, multiply by common denominator, which is 30.

45x + 6x = 55x - 4
51x = 55x - 4
51x - 55x = -4
-4x = -4
x = -4/-4
x = 1

4 0
3 years ago
Read 2 more answers
Point M is located at (-6,6).<br> What is located 5 units from point M?
timurjin [86]
Do you have a picture? Normally this kind of problem features a graph with other points included. -1,6? -6,1? -11,6? -6,11?
6 0
2 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
3 years ago
How would I do this?
Georgia [21]
Work shown above! Answer would be 110 degrees!

3 0
3 years ago
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