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pochemuha
3 years ago
9

Drag the correct number of pieces to show how to find the area of the shaded figure in two different ways. Pieces can be rotated

to fit.

Mathematics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

1st scenario

2 of the 1st

2 of the 3rd

1 of the 5th

2 scenario

1 of 2nd

1 of the 5th

Step-by-step explanation:

Firdavs [7]3 years ago
6 0
Rotate the second shape upside down and put the triangle on top
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What is the surface area of the cylinder with height 6 in and radius 7 in? Round your answer to the nearest thousandth.
Dennis_Churaev [7]

Answer:

571.77

Step-by-step explanation: I might be wrong so don't really trust me

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3 years ago
A triangle has sides with lengths of 8 kilometers, 11 kilometers, and 12 kilometers. Is it a
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The angles equal 76.592, 40.415, 63.056. Use Law of Cosines to find angles.
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2 years ago
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Find the number of bricks to be laid in a square path of side 18cm if the side of each square bricks is 3cm
AlladinOne [14]

Answer:

36 bricks

Step-by-step explanation:

We are given;

  • Length of the square path as 18 cm
  • Length of the square brick as 3 cm

We are required to determine the number of bricks that would be laid on the square path.

Number of bricks = Area of the path ÷ area of one brick

Area of a square = l²

Therefore;

Area of the square path = (18 cm)²

                                        = 324 cm²

Area of square brick = (3 cm)²

                                   = 9 cm²

Therefore;

Number of bricks = 324 cm² ÷ 9 cm²

                             = 36 bricks

7 0
2 years ago
Which table shows a proportional relationship between x and y?
nekit [7.7K]

Answer:

first one

Step-by-step explanation:

graph is a straight line

5 0
2 years ago
Can someone help me with one pleaseT (ToT)
uysha [10]

Answer:

Add 1 to both sides.

Multiply both sides by -2.

Add 8 to both sides.

Divide both sides by 5.

Step-by-step explanation:

<u>Step 1</u>

-\dfrac{1}{2}(5x-8)-1=6\quad \quad \textsf{Write the equation.}

<u>Step 2</u>

-\dfrac{1}{2}(5x-8)=7 \quad \quad \textsf{Add 1 to both sides.}

This is called the <u>Addition Property of Equality</u>.  When the same number is added to both sides of an equation, the two sides remain equal.

\implies -\dfrac{1}{2}(5x-8)-1+1=6+1

\implies -\dfrac{1}{2}(5x-8)=7

<u>Step 3</u>

5x-8=-14 \quad \quad \textsf{Multiply both sides by -2.}

This is called the <u>Multiplication Property of Equality</u>.  When both sides of an equation are multiplied by the same number, the two sides remain equal.

\implies -2 \cdot -\dfrac{1}{2}(5x-8)=-2 \cdot 7

\implies 5x-8=-14

<u>Step 4</u>

5x=-6 \quad \quad \textsf{Add 8 to both sides.}

This is called the <u>Addition Property of Equality</u>.  When the same number is added to both sides of an equation, the two sides remain equal.

\implies 5x-8+8=-14+8

\implies 5x=-6

<u>Step 5</u>

x=-\dfrac{6}{5} \quad \quad \textsf{Divide both sides by 5.}

This is called the <u>Division Property of Equality</u>.  When both sides of an equation are divided by the same number, the two sides remain equal.

\implies \dfrac{5x}{5}=\dfrac{-6}{5}

\implies x=\dfrac{-6}{5}

<u>Conclusion</u>

<u></u>

<u />\begin{aligned}-\dfrac{1}{2}(5x-8)-1 & =6 & \quad \quad& \textsf{Write the equation.}\\\\-\dfrac{1}{2}(5x-8) & =7 & & \boxed{\textsf{Add 1 to both sides.}}\\\\5x-8 & =-14 & & \boxed{\textsf{Multiply both sides by -2.}}\\\\5x & =-6 & & \boxed{\textsf{Add 8 to both sides.}}\\\\x & =-\dfrac{6}{5} & & \boxed{\textsf{Divide both sides by 5.}}\\\end{aligned}

Learn more about Property Laws here:

brainly.com/question/28255621

brainly.com/question/28210762

5 0
1 year ago
Read 2 more answers
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