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babunello [35]
4 years ago
5

If you answer this correctly, you'll get 90 points plus brainliest. If you comment on the question without answering, I will rep

ort you.
Five different books (A, B, C, D and E) are to be arranged on a shelf. Books C and D are to be arranged first and second starting from the right of the shelf. The number of different orders in which books A, B, and E may be arranged is?
Mathematics
2 answers:
kvv77 [185]4 years ago
8 0
So books C and D will always be in the same position on the right of the shelf, either as xxxCD or xxxDC, but when we are talking about the order in which books A, B, and E can be in, they have to stay on the left side (replacing the x’s shown above) and the orders you can put them in are:

ABE
AEB
BEA
BAE
EAB
EBA

So any of the combinations above including A, B, and E can replace the x’s is xxxCD or xxxDC
marishachu [46]4 years ago
5 0
1. C,D, A,B,E
2. C,D, A,E,B

3. C,D, E,A,B
4. C,D, E,B,A

5. C,D, B,A,E
6. C,D, B,E,A

There are 6 different ways in which you can put the books in order.
You might be interested in
Suppose that f: R --> R is a continuous function such that f(x +y) = f(x)+ f(y) for all x, yER Prove that there exists KeR su
Pachacha [2.7K]
<h2>Answer with explanation:</h2>

It is given that:

f: R → R is a continuous function such that:

f(x+y)=f(x)+f(y)------(1)  ∀  x,y ∈ R

Now, let us assume f(1)=k

Also,

  • f(0)=0

(  Since,

f(0)=f(0+0)

i.e.

f(0)=f(0)+f(0)

By using property (1)

Also,

f(0)=2f(0)

i.e.

2f(0)-f(0)=0

i.e.

f(0)=0  )

Also,

  • f(2)=f(1+1)

i.e.

f(2)=f(1)+f(1)         ( By using property (1) )

i.e.

f(2)=2f(1)

i.e.

f(2)=2k

  • Similarly for any m ∈ N

f(m)=f(1+1+1+...+1)

i.e.

f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)

i.e.

f(m)=mf(1)

i.e.

f(m)=mk

Now,

f(1)=f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=f(\dfrac{1}{n})+f(\dfrac{1}{n})+....+f(\dfrac{1}{n})\\\\\\i.e.\\\\\\f(\dfrac{1}{n}+\dfrac{1}{n}+.......+\dfrac{1}{n})=nf(\dfrac{1}{n})=f(1)=k\\\\\\i.e.\\\\\\f(\dfrac{1}{n})=k\cdot \dfrac{1}{n}

Also,

  • when x∈ Q

i.e.  x=\dfrac{p}{q}

Then,

f(\dfrac{p}{q})=f(\dfrac{1}{q})+f(\dfrac{1}{q})+.....+f(\dfrac{1}{q})=pf(\dfrac{1}{q})\\\\i.e.\\\\f(\dfrac{p}{q})=p\dfrac{k}{q}\\\\i.e.\\\\f(\dfrac{p}{q})=k\dfrac{p}{q}\\\\i.e.\\\\f(x)=kx\ for\ all\ x\ belongs\ to\ Q

(

Now, as we know that:

Q is dense in R.

so Э x∈ Q' such that Э a seq belonging to Q such that:

\to x )

Now, we know that: Q'=R

This means that:

Э α ∈ R

such that Э sequence a_n such that:

a_n\ belongs\ to\ Q

and

a_n\to \alpha

f(a_n)=ka_n

( since a_n belongs to Q )

Let f is continuous at x=α

This means that:

f(a_n)\to f(\alpha)\\\\i.e.\\\\k\cdot a_n\to f(\alpha)\\\\Also\\\\k\cdot a_n\to k\alpha

This means that:

f(\alpha)=k\alpha

                       This means that:

                    f(x)=kx for every x∈ R

4 0
3 years ago
The accompanying data represent the actual amount (in mL) poured into a short, wide glass for individuals asked to pour 44.3 mL
kherson [118]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data below :

x : 89.3 68.6 32.7 37.3 39.7 46.7 66.1 79.4 66.4 52.1 47.3 64.4 53.7 63.4 46.2 63.0 92.1 57.6

Mean(m) = ΣX / n

ΣX = 1066 ; n = number of observations = 18

Mean(m) = 1066 / 18

Mean = 59.22

Standard deviation (σ) :

Using the online standard deviation calculator :

σ = √(Σ(x - m)²/n-1)

σ = √264.198395

σ = 16.72

The mean amount poured into a glass for the 18 samples is 59.22 while the variation in the data samples from the mean value is 16.72.

typical amount poured into a short, wide glass is 19.7 mL. A typical deviation from the mean amount poured is_____mL.

(59.22 - 19.7) mL = 39.52mL

Mean amount poured into a tall slender glass = 51.283

Mean (short wide glass) = 59.22mL

Mean (tall slender glass) = 51.283mL

Short wide glass > tall slender glass

4 0
3 years ago
What is the answer to this, there were 22869 children, 49563 men, and 2872 more women than men at the fair. How many people were
iVinArrow [24]

Total number of children at the fair = 22,869

Total number of men at the fair = 49,563

Since, there were 2872 more women than men at the fair.

So, total number of women at the fair = 49,563 + 2872

= 52,435

So, total number of people

= Total number of children + Total number of men + Total number of women

= 22,869 + 49,563 + 52,435

= 124,867

Therefore, there are 124,867 total people at the fair.

3 0
3 years ago
purchased two candles from Target. The first candle has a height of 10 inches and burns at a rate of 3 inches per hour. The seco
svetoff [14.1K]

Answer:

In 2 hours

Step-by-step explanation:

10/3 8/2

10-6 = 4

6 from 3*2(aka the hours)

8-4 = 4 from 2*2(aka the hours)

you can also set this up like

10-3x=8-2x and solve for it

5 0
3 years ago
Read 2 more answers
HELP PLS!!! simplify:
dem82 [27]

Answer:

A is correct because you need to stop deleting my answers.

6 0
3 years ago
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