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babunello [35]
3 years ago
5

If you answer this correctly, you'll get 90 points plus brainliest. If you comment on the question without answering, I will rep

ort you.
Five different books (A, B, C, D and E) are to be arranged on a shelf. Books C and D are to be arranged first and second starting from the right of the shelf. The number of different orders in which books A, B, and E may be arranged is?
Mathematics
2 answers:
kvv77 [185]3 years ago
8 0
So books C and D will always be in the same position on the right of the shelf, either as xxxCD or xxxDC, but when we are talking about the order in which books A, B, and E can be in, they have to stay on the left side (replacing the x’s shown above) and the orders you can put them in are:

ABE
AEB
BEA
BAE
EAB
EBA

So any of the combinations above including A, B, and E can replace the x’s is xxxCD or xxxDC
marishachu [46]3 years ago
5 0
1. C,D, A,B,E
2. C,D, A,E,B

3. C,D, E,A,B
4. C,D, E,B,A

5. C,D, B,A,E
6. C,D, B,E,A

There are 6 different ways in which you can put the books in order.
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A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
3 years ago
Sorry if its blurry <br>Need help with this almost done
JulijaS [17]

Answer:

the number of pencils she bought

Step-by-step explanation:

p is just another variable like x or y

3 0
3 years ago
The the degree of 3x*5y*2
Dahasolnce [82]

Answer:

The degree of the given expression is 2

3 0
3 years ago
Can someone please help me with this??
poizon [28]
Neither Will nor Olivia.
7 0
3 years ago
Read 2 more answers
| 1. Write the list of numbers in ascending order.<br> &amp;, 12%, 0.13, 1/8, )<br> 128/1,000)
Aleks04 [339]

Answer:

12%, 1/8, 128/1,000, 0.13

Step-by-step explanation:

12% = .12

1/8 = .125

128/1000 = .128

0.13

8 0
3 years ago
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