Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:

Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:

![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
10⁵ billion
Step-by-step explanation:
given that distance from sun to earth
= 1.5 x 10⁸ km (we need to convert this to millimeters)
= 1.5 x 10⁸ km x 1 million mm per km
= 1.5 x 10⁸ km x 1,000,000 mm/km
= 1.5 x 10⁸ km x 10⁶ mm/km
= 1.5 x 10⁸ x 10⁶
= 1.5 x 10⁽⁸ ⁺ ⁶⁾
= 1.5 x 10¹⁴ mm
also given that a quarter is 1.5mm thick, hence the number of quarters that will span the distance between the sun an earth (i.e 1.5 x 10¹⁴ mm)
= 1.5 x 10¹⁴ mm ÷ 1.5 mm/quarter
= 10¹⁴
= 100,000,000,000,000 (remember that a billion has 9 zeros)
= 100,000 billion
= 10⁵ billion
Answer:
a) π
b) 33.4
Step-by-step explanation:
C = πd
1) substitute 105 for C: 105 = πd
2) plug in approximate value of 3.14 for π: 105 = (3.14) d
3) isolate to solve for d: 105/3.14 = d
4) simplify: 105/3.14 ≈ 33.4
Answer: 2.34 is written as a decimal form.
Step-by-step explanation: two and thirty-four hundredths