HELP PLS!!! simplify:

Mathematics

1 answer:

dem82 [27]3 years ago

6 0

Answer:

A is correct because you need to stop deleting my answers.

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Find the area to the nearest square foot of the shaded region below, consisting of a square with a circle cut out of it. Use

Simora [160]

Answer:

the area is 10 feet by 10 feet, 100 feet²

subtract the area of the circle from this.

you get it by A = r² * pi

so 5² * 3.14159...

=78.5398163397

100-78.5398163397

is roughly 21.46 square feet

7 0

3 years ago

(WILL GIVE BRAINLIEST) In right ∆ABC with m∠B=30°, AC = 4. Find HB

goblinko [34]

Answer:

HB would be 90 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I need help I can’t figure it out

dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$