Question

Can I get some help with this question? Solve 3(x + 2) > x.

Answer 1

Answer:

$\large\boxed{x>-3\to\{x\ |\ x>-3\}\to x\in(-3,\ \infty)}$

Step-by-step explanation:

$3(x+2)>x\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\(3)(x)+(3)(2)>x\\\\3x+6>x\qquad\text{subtract 6 from both sides}\\\\3x+6-6>x-6\\\\3x>x-6\qquad\text{subtract x from both sides}\\\\3x-x>x-x-6\\\\2x>-6\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}>\dfrac{-6}{2}\\\\x>-3$

Answer 2

Answer:

x > -3

Step-by-step explanation:

We are given the following inequality that we are to solve:

$3(x+2)>x$

Applying the distributive property of multiplication on the left side of the inequality to get:

$3 x + 6 > x$

Rearranging the inequality:

$3 x - x > - 6$

$2 x > - 6$

$x > \frac { - 6 } { 2 }$

x > -3