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3 years ago

12

8. If3:8=c:56, the value of c will be

1 answer:

adelina 88 [10]3 years ago

6 0

The scale for the second values is 56/8 = 7

C = 3 x 7 = 21

C= 21

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A student has learned that test scores in math are determined by this quadratic function: s(t) = -(t-6)^2 + 99

ser-zykov [4K]

Answer:

a. 6, b. 99, c. 63

Step-by-step explanation:

A) The function s(t) is in the vertex form. The standard vertex form is a(x-h)+k where the vertex is (h,k). The vertex is the highest (or lowest in some cases) point of the graph, so if we use s(t) to get the vertex we get that h=6 and k=99. This means that for a student to get a perfect score they need to study 6 hours

B) We can just take the k value from the first question because that's the highest value for s(t), so the highest score will be 99

C) For this one just plug in 0 for time, so -(0-6)^2+99. This equals -(-6)^2+99, which equals 99-36 =63

4 0

3 years ago

What is the value 7?

xeze [42]

Answer:

are u asking the absolute value ??? if so.. |7|

Step-by-step explanation:

3 0

3 years ago

A piece of brass contains 1.66 grams of copper and 0.34 gram of

drek231 [11]

Answer:

2.00 grams

Step-by-step explanation:

1.66 + 0.34 = 2.00

2.00 grams

3 0

2 years ago

Given function of f(x) = 2x - 1 and fg(x) = 10x + 3, find the function of g(x)

denis-greek [22]

Answer:

The function of g(x) = 5x + 2

Step-by-step explanation:

Let us use the composite function to solve the question

∵ f(x) = 2x - 1

∵ f(g(x)) = 10x + 3

→ f(g(x)) means substitute x in f(x) by g(x)

∴ f(g(x)) = 2[g(x)] - 1

→ Equate the two right sides of f(g(x))

∴ 2[g(x)] - 1 = 10x + 3

→ Add 1 to both sides

∴ 2[g(x)] - 1 + 1 = 10x + 3 + 1

∴ 2[g(x)] = 10x + 4

→ Divide each term into both sides by 2

∵ $\frac{2[g(x)]}{2}$ = $\frac{10x}{2}$ + $\frac{4}{2}$

∴ g(x) = 5x + 2

∴ The function of g(x) = 5x + 2

7 0

2 years ago

Find the missing side of this right a triangle?<br> help pls

yaroslaw [1]

Hi, there!

_____

To find the missing side length of this triangle (which is a <em>right</em> triangle), we'll use Pythagoras' Theorem.

$-\!\!\!-\!\!\!-\!\!\!\longrightarrow\boldsymbol{a^2+b^2=c^2}$

Here,

$\textsc{legs:}\begin{cases} \bold{a}\\\bold{b} \end{cases}$

Hypotenuse (the longest side): c

We know that

$\bold{a=2 \ and \ b=28}$

So, we can substitute our parameters, and solve for c.

$\bold{2^2+28^2=c^2}$ $-\!\!\!-\!\!\!-\!\!\!\longrightarrow$ square 2 and 28

$\bold{4+784=c^2}$ $-\!\!\!-\!\!\!-\!\!\!\longrightarrow$ add the numbers

$\bold{788=c^2}$ $-\!\!\!-\!\!\!-\!\!\!\longrightarrow$ square root both sides

$\bold{\sqrt{788}=c}$

Hope the answer - and explanation - made sense,

happy studying!!

6 0

2 years ago