The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Ken grew .425 of an inch more than sang because 4/5 is .8 and 3/8 is .375 what you do is you take those two numbers and subtract the smaller one from the bigger one and you get .425 and ken had the bigger growth. plz rate me brainliest
28.3 / 9 = 3.14444444......
3.14 round to 3
Answer:
100*.025*3=7.5 100+7.5=107.5
100*.02*3=6 100+6=106
107.5-106=1.5
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Step-by-step explanation:
thats it
Answer:
7, 616 because there is no floating point