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Norma-Jean [14]
3 years ago
15

When a customer makes a request or complaint, the goal of customer service is to:

Computers and Technology
2 answers:
elena55 [62]3 years ago
7 0

Answer:

The answer is "Option D"

Explanation:

Customer service is a resource, in which the consumers shall be provided before during transactions. The purpose of this service is to teach the customer how to remain calm and courteous. It acts as customer support as the very first point of access to consumers with issues, and certain alternative is wrong, which can be described as follows:

  • It can't provide any type of relation.
  • It only provides help and support, that's why it is wrong.
  • It is wrong because it satisfies the customer, then cut the phone call.

yan [13]3 years ago
3 0

Answer:

option number 4

Explanation:

edgenuity

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Assume that getPlayer2Move works as specified, regardless of what you wrote in part (a) . You must use getPlayer1Move and getPla
kakasveta [241]

Answer:

(1)

public int getPlayer2Move(int round)

{

  int result = 0;

 

  //If round is divided by 3

  if(round%3 == 0) {

      result= 3;

  }

  //if round is not divided by 3 and is divided by 2

  else if(round%3 != 0 && round%2 == 0) {

      result = 2;

  }

  //if round is not divided by 3 or 2

  else {

      result = 1;

  }

 

  return result;

}

(2)

public void playGame()

{

 

  //Initializing player 1 coins

  int player1Coins = startingCoins;

 

  //Initializing player 2 coins

  int player2Coins = startingCoins;

 

 

  for ( int round = 1 ; round <= maxRounds ; round++) {

     

      //if the player 1 or player 2 coins are less than 3

      if(player1Coins < 3 || player2Coins < 3) {

          break;

      }

     

      //The number of coins player 1 spends

      int player1Spends = getPlayer1Move();

     

      //The number of coins player 2 spends

      int player2Spends = getPlayer2Move(round);

     

      //Remaining coins of player 1

      player1Coins -= player1Spends;

     

      //Remaining coins of player 2

      player2Coins -= player2Spends;

     

      //If player 2 spends the same number of coins as player 2 spends

      if ( player1Spends == player2Spends) {

          player2Coins += 1;

          continue;

      }

     

      //positive difference between the number of coins spent by the two players

      int difference = Math.abs(player1Spends - player2Spends) ;

     

      //if difference is 1

      if( difference == 1) {

          player2Coins += 1;

          continue;

      }

     

      //If difference is 2

      if(difference == 2) {

          player1Coins += 2;

          continue;

      }

     

     

  }

 

  // At the end of the game

  //If player 1 coins is equal to player two coins

  if(player1Coins == player2Coins) {

      System.out.println("tie game");

  }

  //If player 1 coins are greater than player 2 coins

  else if(player1Coins > player2Coins) {

      System.out.println("player 1 wins");

  }

  //If player 2 coins is grater than player 2 coins

  else if(player1Coins < player2Coins) {

      System.out.println("player 2 wins");

  }

}

3 0
3 years ago
Implement a recursive method named power that takes 2 integer parameters named base and expo. The method will return the base ra
nika2105 [10]

Answer:

def power(base, expo):

   if expo == 0:

       return 1

   else:

       return base * power(base, expo-1)

Explanation:

*The code is in Python.

Create a method called power that takes base and expo as parameters

Check if the expo is equal to 0. If it is return 1 (This is our base case for the method, where it stops. This way our method will call itself "expo" times). If expo is not 0, return base * power(base, expo-1). (Call the method itself, decrease the expo by 1 in each call and multiply the base)

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Answer:

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Heelo how do u do python syntax lesson 11 on code academy
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have you tried www.khanacademy.org 


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