The mean is 6 and the mode is 5
The volume formula could be re-written to help understand this, as V = π*3r^2*3h. If you solve for this, you can conclude that the volume would be multiplied by 27.
Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
The expression simplifies to 6x^(28/5)
hope this helps :)
Answer:
Step-by-step explanation:
The slope formula is 
Here, 
is -6, 
is 4, 
is -5, and 
is 4.
So, the slope of the line passing through the points (-6,-5) and (4,4) is .
