F(x) = 3x + 11
Is the function used to show this.
when you know this, you are able to do the following:
f(10) = 30 + 11 = $41
That would be the allowance of the 10th week.
The question, however wants the total.
This again, can be done like this:
f(1) + f(2) + f(3) + f(4) + f(5) + f(6) + f(7) + f(8) + f(9) + f(10) = $275 :)
14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 = $275
Sure there is a better formula, but i couldnt seem to make it, sorry.
HUGE UPDATE: The sum is $275 not 200..
F(x,y)=8x+y
This means, f is a function where we plug in pairs of numbers.
then, f calculates the first number times 8, to which it then adds the second number we plugged.
let's calculate f for the vertices:
f(0,0)=8*0+0=0+0=0
f(4, 0)=8*4+0=32+0=32
f(3, 5)=8*3+5=24+5=29
f(0, 5)=8*0+5=0+5=5
the maximum value of f is 32
the minimum value of f is 0
Answer:
x = 1 or x = -5
Step-by-step explanation:
We are given;
- The quadratic equation, x² + 4x - 13 = -8
We are required to solve the equation using the completing square method.
To do this, we use the following steps;
Step 1: We make sure the coefficient of x² is one
x² + 4x - 13 = -8
Step 2: Combine the like terms (take the constant term to the other side)
x² + 4x - 13 = -8
x² + 4x = -8 + 13
we get
x² + 4x = 5
Step 3: We add the square of half the coefficient of x on both sides of the equation
Coefficient of x = 4
Half of coefficient of x = 2
Square of half the coefficient of x = 2² (4)
We get;
x² + 4x + (2²) = 5 + (2²)
Step 4: Put x and 2 under one square and the solve the other side of the equation.
We get
(x + 2)² = 5 + 4
(x + 2)² = 9
Step 5: Get the square root on both sides of the equation;
(x + 2)² = 9
√(x + 2)² = ±√9
(x + 2)= ±3
Therefore;
x+2 = + 3 or x + 2 = -3
Thus, x = 1 or -5
The solution of the equation is x = 1 or x = -5
we are given
Since, we have to solve for w
so, we will isolate w on anyone side
Multiply both sides by 5
so,
option-D..........Answer
Answer:
Two possible solutions
Step-by-step explanation:
we know that
Applying the law of sines
we have
step 1
Find the measure of angle A
substitute the values
The measure of angle A could have two measures
the first measure-------> 
the second measure -----> 
step 2
Find the first measure of angle C
Remember that the sum of the internal angles of a triangle must be equal to 
substitute the values
step 3
Find the first length of side c
substitute the values
therefore
the measures for the first solution of the triangle are
,
,
, 
step 4
Find the second measure of angle C with the second measure of angle A
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 5
Find the second length of side c
substitute the values
therefore
the measures for the second solution of the triangle are
,
,
, 
