1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dalvyx [7]
2 years ago
15

Solve the system using elimination.

Mathematics
1 answer:
Shalnov [3]2 years ago
4 0

Answer:

After simplifying we get (x,y) as (1,3).

Step-by-step explanation:

Given:

x+7y=22,

x-7y=-17

We need to use elimination method to solve the and simplify the equations.

Solution;

Let x+7y=22 ⇒ equation 1

Also Let 4x-7y=-17⇒ equation 2

Now by solving the equation we get;

first we will Add equation 2 from equation 1 we get;

(x+7y)+(4x-7y)=22+(-17)\\\\x+7y+4x-7y=22-17\\\\5x=5

Now Dividing  both side by 5 using division property of equality we get;

\frac{5x}{5}=\frac{5}{5}\\\\x=1

Now Substituting the vale of x in equation 1 we get;

x+7y=22\\\\1+7y=22

subtracting both side by 1 using subtraction property of equality we get;

1+7y-1=22-1\\\\7y=21

Now Dividing  both side by 7 using division property of equality we get;

\frac{7y}{7}=\frac{21}{7}\\\\y=3

Hence we can say that, After simplifying we get (x,y) as (1,3).

You might be interested in
Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)
vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

<em>Two angles are said to be supplementary when they add up to 180°.</em>

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

<em>Two angles are said to be complementary when they add up to 90°.</em>

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0
3 years ago
What is the circumference of a circle with a diameter 9cm
xz_007 [3.2K]
The circumference follows the formula
C= 2 (pi)R
R is the radius which is half the diameter when we put this into the equation we get
C = 2 (pi)(4.5)
C=28.274334
5 0
3 years ago
Read 2 more answers
Solve for x 2/3=x/4<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%20%20%7D%20%20%3D%20%20%5Cfrac%7Bx%7D%7B4%20%7D%2
balandron [24]
To solve this, you cross multiply, then divide. In this case, we multiply 4 and 2, then divide by 3.

4 x 2 = 8
8 / 3 = 2.66

So, x is 2.66
3 0
3 years ago
Nine years less than 5 times the age a
hichkok12 [17]
5a-9
I think this is the answer I am a little unsure of what the question is.
4 0
3 years ago
Read 2 more answers
What is the simplified form of the following expression?
USPshnik [31]

Option C:

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

Solution:

Given expression is

$\sqrt[3]{\frac{4 x}{5}}

Note: \sqrt[3]{125}=\sqrt[3]{{5^3}}  = 5

To find the correct expression for the above simplified expression.

Option A: \frac{\sqrt[3]{4 x}}{5}

5 can be written as \sqrt[3]{125}.

$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }

       $=\sqrt[3]{\frac{4x}{125} }

It is not the given simplified expression.

Option B: \frac{\sqrt[3]{20 x}}{5}

$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }

         $=\sqrt[3]{\frac{20x}{125} }

Cancel the common factor in both numerator and denominator.

         $=\sqrt[3]{\frac{4x}{25} }

It is not the given simplified expression.

Option C: \frac{\sqrt[3]{100 x}}{5}

$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }

           $=\sqrt[3]{\frac{100x}{125} }

Cancel the common factor in both numerator and denominator.

           $=\sqrt[3]{\frac{4 x}{5}}

It is the given simplified expression.

Option D: \frac{\sqrt[3]{100 x}}{125}

$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}

It is not the given simplified expression.

Hence Option C is the correct answer.

$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}

3 0
3 years ago
Other questions:
  • What is the selling price or the cost price depending on the information if the selling price is $21 and the game is 5%?
    14·1 answer
  • HELP ME PLZZ I NEED HELP WITH THIS
    10·1 answer
  • Help with this algebra question please <br> thank you
    11·2 answers
  • The length of a rectangle is 5 m longer than its width. If the perimeter of the rectangle is 46 m , find its area.
    10·1 answer
  • Describe the relationship between the value of (126+9) and (126+9) / 2.
    15·2 answers
  • What does the square root of 3 plus the square root of 3 give you?
    8·1 answer
  • Hiii need help I'm in exam​
    13·1 answer
  • 3 ounces for every 3/4 cup
    7·1 answer
  • The lawn is a circle with radius 3m.<br> Work out the area of the lawn.
    11·1 answer
  • Ian puts 300.00 into an account to use for school expenses the account earns 6%interest compounded annually how much will be in
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!