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kenny6666 [7]
2 years ago
6

PLEASE HELP 20 POINTS

Mathematics
2 answers:
Anika [276]2 years ago
7 0
Hello!

A sample of Bromine-82 begins at 80 mL. We are given that this value will decrease by half of its current amount every 35 hours. First, we'll determine the number of times that 35 goes into 140. This will reveal the number of times we should divide the sample by 2:

140 ÷ 35 = 4

We have now proven that there are 4 periods of 35 hours in 140 hours. This means that we will divide the sample in half a total of 4 times, as follows:

1. 80 ÷ 2 = 40
2. 40 ÷ 2 = 20
3. 20 ÷ 2 = 10
4. 10 ÷ 2 = 5

We have now proven that an 80 mL sample of Bromine-82 will be reduced to only 5 mL after 140 hours. Therefore, the correct answer is 5 mL.

I hope this helps!
PSYCHO15rus [73]2 years ago
3 0
To solve this problem, we have to use the half-life formula, where <em>A</em> represents the remaining amount, <em>P</em> is the initial amount, <em>t</em> is the time that has passed, and <em>h</em> is the substance's half-life:

A = P( \frac{1}{2} )^{\frac{t}{h} }

This is what it looks like with the values from this scenario plugged in:

A = 80( \frac{1}{2} )^{\frac{140}{35} } \\ A = 5

There are 5 mL of the 80 mL Bromine sample left after 140 hours.
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List all the possible rational zeros of p(x)=3x^3-3x^2+4x-12
skelet666 [1.2K]

Answer:

x = 3

x)=x^3-3x^2-4x+12  \\ 0 = 3x ^2 - 3x ^2 + 4x - 12 \\ 0 = 4x - 12 \\  - 4x =  - 12 \\  - x =  - 12 \div 4 \\ x = 3

3 0
2 years ago
If you multiply two even numbers where the product be even or odd explain with an example
dybincka [34]

Answer:

Even

Step-by-step explanation:

Any two numbers you multiply together that are both even will always result in an even number. For example 48x24=1152. You can use any two even numbers and you will always get and even product.

8 0
3 years ago
Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x
fredd [130]

Answer:

The solution of the inequation 6\cdot x^{2} \geq 10 + 11\cdot x is \left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right).

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

6\cdot x^{2} \geq 10 + 11\cdot x

6\cdot x^{2}-11\cdot x -10 \geq 0

6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0

Roots are found by Quadratic Formula:

r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}

r_{1} = \frac{5}{2} and r_{2} = -\frac{2}{3}

Then, the factorized form of the inequation is:

6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0

By Real Algebra, there are two condition that fulfill the inequation:

a) x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0

x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}

x \geq \frac{5}{2}

b) x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0

x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}

x\leq -\frac{2}{3}

The solution of the inequation 6\cdot x^{2} \geq 10 + 11\cdot x is \left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right).

3 0
3 years ago
What are the areas of each smaller rectangle and the large rectangle?
zhannawk [14.2K]

Answer:

Area of part 1: 3 * 5\sqrt{2} = 15\sqrt{2}

Area of part 2: 3\sqrt{2} * 5\sqrt{2}=30

Area of entire rectangle: 30 + 15\sqrt{2}

Step-by-step explanation:

The area of a rectangle can be found by using formula : length * width.

The area of part 1 can be simplified to this:

3 * 5\sqrt{2} = 15\sqrt{2}

Area of part 2:

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The area of the entire rectangle can simply be added from part 1 and part 2.

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7 0
3 years ago
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Answer:

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Step-by-step explanation:

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The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.

If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.

So we have

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160 + 48

208 in^2

5 0
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