3 years ago

tell whether the system has one solution, infinitely many solutions, or no solution. x = -7y + 24 x + 7y = 32

1 answer:

7 0

This system has no solution.
x = -7y + 24 can be rewritten as x = 24 - 7y
to simplify x + 7y = 32, we have to subtract 7y from both sides
x = 32 - 7y
Now, our system is as follows:
x = 24 - 7y
x = 32 - 7y

You might be interested in

Which of the following employees derives their income from a fee for the items sold?

dezoksy [38]

Answer:

commission

Step-by-step explanation:

3 0

3 years ago

Practice Writing Composite Functions Given: f(x) = x - 7 and h(x) = 2x + 3 Write the rule for h(f(x)).

Setler79 [48]

Answer:

Step-by-step explanation:

f(x) = x - 7

h(x) = 2x + 3

To find h(f(x)) substitute f(x) into h(x) that's replace every x in h(x) by f(x)

That's

h(f(x)) = 2(x - 7) + 3

h(f(x)) = 2x - 14 + 3

We have the final answer as

Hope this helps you

6 0

3 years ago

Pls Help ASAP if you. Can

n200080 [17]

I think it’s b because it would make the most sense I believe but I’m really sorry if I’m wrong

5 0

3 years ago

RES<br> Find (fºg)(1)<br> Ax) = x2 - 1<br> g(x)= v<br> a 0<br> c. 4.<br> b.<br> d. 18<br> Help pls

slava [35]

Answer:

Step-by-step explanation:

So we have the two functions:

$f(x)=x^2-1\\g(x)=\sqrt x$

And we want to find:

$(f\circ g)(1)$

This is the same as:

$f(g(1))$

So, to find the answer, find g(1) first:

$g(x)=\sqrt x\\g(1)=\sqrt1\\g(1)=1$

Now, substitute this value for g(1):

$f(g(1))\\=f(1)$

And plug this into f(x):

$f(x)=x^2-1\\f(1)=(1)^2-1\\f(1)=1-1=0$

Therefore:

$f(1)=f(g(1))=(f\circ g)(1)=0$

Our answer is A

3 0

3 years ago

Read 2 more answers

How can you minimize the risk from investment?

adoni [48]

Don’t invest too much into it

3 0

3 years ago

Read 2 more answers