Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Answer:
The muscle cell need to use most entry in a typical day
The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.
The balanced chemical equation for the dissolution of silver nitrate has been:
The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.
In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.
From, the balanced equation,
The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:
The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.
For more information about the moles produced, refer to the link:
brainly.com/question/10606802
Answer:
To calculate the volume we must first find the number of moles
Number of moles (n ) = mass / Molar mass (M)
Since oxygen is diatomic
M of oxygen = 16 × 2 = 32g/mol
n = 16 / 32 = 0.5mol
Next we use the formula
V = n × V(dm³)
where V is the volume
V(dm³) is the volume of 1 mole of a substance at s.t.p which is
22.4dm³
Volume of oxygen gas at s.t.p is
0.5 × 22.4dm³
= 11.20dm³
Hope this helps you
helium, beryllium, magnesium, calcium, strontium, barium, radium. i believe any of these are proper answers.
