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3 years ago

What is bulimia? can someone explain it to me.

2 answers:

4 0

It is an emotional disorder involving distortion of body image and an obsessive desire to lose weight, in which bouts of extreme overeating are followed by depression and self-induced vomiting, purging, or fasting.The exact cause of bulimia is currently unknown; though it is thought that multiple factors contribute to the development of this eating disorder, including genetic, environmental, psychological, and cultural influences. Some of the main causes for bulimia include:
Stressful transitions or life changes
History of abuse or trauma
Negative body image
Poor self-esteem
Professions or activities that focus on appearance/performance

Serjik [45]3 years ago

3 0

Answer:

It is a obsessive eating disorder. Where one eats over the average amount and then makes themselves vomit. This is called purging. It is one of 3 main eating disorders. It is a very complex and misunderstood disease. One typically confuses it with binge eating or anorexia.

You might be interested in

How many molecules are in 1.75 moles of Caco3?

saw5 [17]

Answer:

1.054 x 10²⁴ molecules

Explanation:

In order to convert moles of any given substance into a number of molecules, we need to use Avogadro's number, which states the number of molecules -or atoms, in the case of elements- present in one mol:

In one mol there are 6.023x10²³ molecules.

We now convert 1.75 moles into molecules:

1.75 mol * 6.023x10²³ molecules/mol = 1.05x10²⁴ molecules

5 0

2 years ago

Calculate the EMF between copper and silver Ag+e-E=0.89v Cu=E=0.34v

bogdanovich [222]

Answer:

Depending on the $E^\circ$ value of $\rm Ag^{+} + e^{-} \to Ag\; (s)$ , the cell potential would be:

$0.55\; \rm V$ , using data from this particular question; or
approximately $0.46\; \rm V$ , using data from the CRC handbooks.

Explanation:

In this galvanic cell, the following two reactions are going on:

The conversion between $\rm Ag\; (s)$ and $\rm Ag^{+}$ ions, $\rm Ag^{+} + e^{-} \rightleftharpoons Ag\; (s)$ , and
The conversion between $\rm Cu\; (s)$ and $\rm Cu^{2+}$ ions, $\rm Cu^{2+}\; (aq) + 2\, e^{-} \rightleftharpoons \rm Cu\; (s)$ .

Note that the standard reduction potential of $\rm Ag^{+}$ ions to $\rm Ag\; (s)$ is higher than that of $\rm Cu^{2+}$ ions to $\rm Cu\; (s)$ . Alternatively, consider the fact that in the metal activity series, copper is more reactive than silver. Either way, the reaction is this cell will be spontaneous (and will generate a positive EMF) only if $\rm Ag^{+}$ ions are reduced while $\rm Cu\; (s)$ is oxidized.

Therefore:

The reduction reaction at the cathode will be: $\rm Ag^{+} + e^{-} \to Ag\; (s)$ . The standard cell potential of this reaction (according to this question) is $E(\text{cathode}) = 0.89\; \rm V$ . According to the 2012 CRC handbook, that value will be approximately $0.79\; \rm V$ .

The oxidation at the anode will be: $\rm Cu\; (s) \to \rm Cu^{2+} + 2\, e^{-}$ . According to this question, this reaction in the opposite direction ( $\rm Cu^{2+}\; (aq) + 2\, e^{-} \rightleftharpoons \rm Cu\; (s)$ ) has an electrode potential of $0.34\; \rm V$ . When that reaction is inverted, the electrode potential will also be inverted. Therefore, $E(\text{anode}) = -0.34\; \rm V$ .

The cell potential is the sum of the electrode potentials at the cathode and at the anode:

$\begin{aligned}E(\text{cell}) &= E(\text{cathode}) + E(\text{anode}) \\ &= 0.89 \; \rm V + (-0.34\; \rm V) = 0.55\; \rm V\end{aligned}$ .

Using data from the 1985 and 2012 CRC Handbook:

$\begin{aligned}E(\text{cell}) &= E(\text{cathode}) + E(\text{anode}) \\ &\approx 0.7996 \; \rm V + (-0.337\; \rm V) \approx 0.46\; \rm V\end{aligned}$ .

5 0

3 years ago

PLEASE ANSWER ASAP!!!!!!! 50 points if the answer is correct!

Ad libitum [116K]

mL acetic acid

mL water

Explanation:

Since

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

mL of vinegar.

Similarly, we have

100

−

being water, so we have

mL of water.

8 0

2 years ago

A brick measures 0.018 dam by 6.5 cm by 17.3 cm. What is the volume of the brick in cubic centimeters

erastova [34]

Answer:

volume of brick= length × breadth × height

=0.000018 ×6.5×17.3

7 0

2 years ago

Elements in Group 18 are known

o-na [289]

Answer:

C the number and placement of the electrons

Explanation:

Elements react with one another because they want to achieve a full valence shell of electrons. The noble gases already have a full valence shell of electrons, so they are unlikely to react with other elements.

6 0

2 years ago