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Makovka662 [10]
3 years ago
12

What is the volume, in ml, of 0.183 mol NH3? (at STP).

Chemistry
2 answers:
Akimi4 [234]3 years ago
8 0

4099 ml of ammonia at STP is formed.

Explanation:

At STP, standard temperature of 273.15 K and a pressure of 1atm an ideal gas occupies 22.4 litres (molar volume) of volume. Since ammonia is categorized as an ideal gas under the STP it will have:

1 mole of NH3 at STP occupies 22.4litres of volume.

0.183 moles will occupy

22.4 x 0.183

= 4.099 litres of ammonia.

To convert litre into milliliter quantity is multiplied by 1000 as 1 litre equals 1000 ml.

so, 4.099 x 1000

= 4099 ml

The volume occupied by 0.183 moles of ammonia is 4099 ml.

Tems11 [23]3 years ago
5 0

The volume of ammonia gas is 4096 mL.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be directly proportional to the temperature and number of moles of the gas molecules. Similarly, the volume occupied by gas molecules will be inversely proportional to pressure.

PV = nRT

So, V = nRT/P

As R = 0.082 L atm mol⁻¹ K⁻¹ , T = 273 K and P = 1 atm with n = 0.183 mol

Then,

V=(0.183*0.082*273)/1

V = 4.096 L = 4096 mL.

Thus, the volume of ammonia gas is 4096 mL.

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Which of the following best describes the uses of private land?
melamori03 [73]

Answer : (C) It can be used for variety of activities and 4es

Explanation: A private land is generally used for any purpose like home, business, office, factories or any other purpose. The land is privately owned by its owner which can use the private land for variety of activities the owner wants. A private land can be used as a farm land, or any other non agriculture purpose like building a factory, converting into home or any other purpose.

7 0
3 years ago
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How many grams are in 1.6 moles of potassium bromide?​
slava [35]

Answer:

190.4g

Explanation:

1.6mol of KBr (119.002g KBr/1 mol) = 190.4g

since you want to find grams, take the molar mass of KBr (119.002) per 1 mol and use it as your conversion factor (119.002g KBr/1 mol) which will then cancel out mols and leave you with grams.

6 0
3 years ago
Find the empirical formula of the following compound: 0.77 mol of iron atoms combined with 1.0 mol of oxygen atoms.
eimsori [14]

The empirical formula is Fe₃O₄.

The empirical formula is the <em>simplest whole-number ratio of atoms</em> in a compound.

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the molar ratio of Fe to O.

I like to summarize the calculations in a table.

<u>Element</u>   <u>Moles</u>    <u>Ratio</u>¹   <u>×3</u>²   <u>Integers</u>³

    Fe         0.77       1         3             3

    O           1.0         1.3      3.9          4

¹ To get the molar ratio, you divide each number of moles by the smallest number (0.77).

² If the ratio is not close to an integer, multiply by a number (in this case, 3) to get numbers that are close to integers.

³ Round off these numbers to integers (3 and 4).

The empirical formula is Fe₃O₄.

7 0
3 years ago
For a particular reaction, ΔH⁰ = − 46.7 kJ/mol and ΔS⁰ = − 123.8 J / (mol ⋅ K). Assuming these values change very little with te
PilotLPTM [1.2K]

Answer:

T = 377.2 K, Less than

Explanation:

The thermodynamic quantity used in predicting whether a reaction is spontaneous or not is the gibbs free energy.

It's relationship with ΔH⁰ and ΔS⁰ is given as;

ΔG° = ΔH° - TΔS°

Basically, a negative value of ΔG° means the reaction is spontaeneous.

To obtain the calculated vale of T,

ΔS° = ΔH°/T

T = ΔH° / ΔS°

T = 377.2 K

Let's calculate the value of ΔG° at that temperature.

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 377.2(− 123.8)

ΔG°  = 0 (approximately, values are due to the rounding off)

At ΔG°  = 0 the reaction is at equilibrium.

To find if the reaction is spontaneous at lower or hugher temperature than the calculated temperature, we would be substituting the value of T with a smaller (random) value and also a larger (random) value.

Larger T (390K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 390(− 123.8)

ΔG°  = - 46700 + 48,282

ΔG° = 1582 J/mol

Smaller T (350K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 350(− 123.8)

ΔG°  = - 46700 + 43330

ΔG° = -3370J/mol

This means the temperature would be lesser than the calculated value for it to be spontaneus.

8 0
3 years ago
If a 2 kg object produces a 16 N force, what is its acceleration?
dolphi86 [110]

Answer:

acceleration (a)=8 m/s square.

7 0
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