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Nuetrik [128]
2 years ago
14

If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the

refrigerator if it released 477J of energy to the room?
Chemistry
1 answer:
SVEN [57.7K]2 years ago
5 0
I don’t know but I wilmfind oue
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CAN SOME ONE HELLLLLLLLLLLLLLLLLLLLLLP WILL GIVE BRAINLIEST TO THE BEST ANSWR FOR THIS AND GIVE AWAY 15 POINTS
lord [1]
1. C
2. C
3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit. 
4. Normal faults are faults where the hanging wall moves in a downward force based on the footwall; they are formed from tensional stresses and the stretching of the crust. Reverse faults are the opposite and the hanging wall moves in an upward force based on the footwall; they are formed by compressional stresses and the contraction of the crust.  Thrust faults are low-angle reverse faults where the hanging wall moves in an upward force based on the footwall; they are formed in the same way as reverse faults. Last, Strike-slip faults are faults where the movement is parallel to the crust of the fault; they are caused by an immense shear stress. 

I hope this helped! These are COMPLEX questions though! =D
8 0
3 years ago
The pressure of 6.00 L of gas increases from 1.50 atm to 2.00 atm. What is the final volume of the gas, assuming constant temper
xeze [42]

Answer:

first we need to convert everything in SI units

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2 years ago
Please give me a clear message on what to do.<br> how do you change your brainly username?
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3 years ago
Read 2 more answers
How many moles of nitrogen are contained in 18.65 L at STP?
stira [4]
1 mole of any gas under STP  ----- 22.4 L

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8 0
3 years ago
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To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid
elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

  • pKa = - Log Ka

∴ <em>C</em> X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒<em> C</em> HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0
3 years ago
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