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GREYUIT [131]
2 years ago
12

Heyyyy lol

Mathematics
2 answers:
aev [14]2 years ago
8 0

Answer:

35

Step-by-step explanation:

10 times 1/10 equals 1, so you don't need that since you are multiplying, but if you do, you end up with 35 x 1, which is still 35

35 is your answer

Hope this helps!

damaskus [11]2 years ago
8 0
35 because 10 x 35 is 350 x .1 is 35
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Melissa walked at a rate of 88 feet per minute. What was her approximate speed to the nearest tenth of a mile per hour?
GREYUIT [131]

Answer:

1.0 mph

Step-by-step explanation:

so there are 60 minutes in an hour

you need to find what her speed is per hour

right now it is per minute

so multiply her current speed by 60

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there are 5280 feet in a mile.

Her current speed is 1 mile per minute

rounded to the nearest tenth of a mile is

1.0 mph

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Ltiply.<br> 5. 20 x 0.25
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Answer:

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Step-by-step explanation:

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3 years ago
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Limit as x approaches infinity: 2x/(3x²+5)
Nonamiya [84]
\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\implies \cfrac{\lim\limits_{x\to \infty}~2x}{\lim\limits_{x\to \infty}~3x^2+5}

now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.

BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.

as the denominator increases faster, since as the lingo goes, "reaches the limit faster than the numerator", the fraction becomes ever smaller an smaller ever going towards 0.

now, we could just use L'Hopital rule to check on that.

\bf \lim\limits_{x\to \infty}~\cfrac{2x}{3x^2+5}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}~\cfrac{2}{6x}

notice those derivatives atop and bottom, the top is static, whilst the bottom is racing away to infinity, ever going towards 0.
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3 years ago
Making use of the fact hat eq. (6.20) is an exact differential expression, show that what is the result of application of this e
nevsk [136]
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