Answer:
22
Step-by-step explanation:
Since x = 2, we can tell that x is equal to 2.
So this is basically asking 7 times 2 plus 8
7(2) + 8 = ?
14 + 8 = 22
Hope this helps!
We all know about the bell curve i.e. normal distribution curve. It is centered about the mean and spread equally on each side.
We describe the area of the curve with the help of standard deviations.
With in 1 standard deviation about the mean i.e. from -1 s.d. (left of mean) to +1 s.d. (right of mean), it covers 68% of the total area of curve.
So, the data that falls outside 1 standard deviation of the mean would be equal to (100% - 68%) i.e. 32%.
So, 32% is the final answer.
Here’s the first few and you can do the rest with the same principles. If you need more help with the last ones then let me know
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
Answer:
-14y^2-154y
Step-by-step explanation:
-14y(y+11)
Distribute
-14y*y + -14y*11
-14y^2-154y
