This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Answer
48,000
Step-by-step explanation:
base(x)
1,200(40)
I think it is c, because the probability is the littlest thing and you add most of it, you are welcome my boy
Do u still need the answer to this problem its been 2 weeks now!!
Hello and Good Morning/Afternoon
<u>Let's take this problem step by step</u>:
<u>To find the rate of change is essentially like finding a line's slope</u>:
⇒ the <em>x-values</em> are the <em>number of sodas</em>
⇒ the<em> y-values </em>are the <em>total costs</em>
<em> ⇒ choose</em> two sets of coordinates and find the slope
<u>Let's put that into action</u>
⇒ (24, 18)
⇒ (28, 21)

<u>Since the rate of change is total cost over number of sodas</u>
⇒ <em>unit is '</em>total cost/number of sodas'
<u>Answer: 3/4 total cost/number of sodas</u>
<u></u>
Hope that helps!
#LearnwithBrainly
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