Answer:
A 404 mi
Step-by-step explanation:
If we designate the points of the triangle A, B, and C for the locations of the western station, eastern station, and balloon, respectively, we have the following:
∠CAB = 90° - 41° = 49°
∠CBA = 90° + 21° = 111°
∠ACB = 41° -21° = 20°
side "c" (opposite ∠ACB) is 148 miles
The distance we're asked to find is AC = b, the longest side of the triangle. The law of sines tells us ...
b/sin(B) = c/sin(C)
b = c·sin(B)/sin(C) = (148 mi)·sin(111°)/sin(20°) ≈ 403.98 mi ≈ 404 mi
Answer:
The people can seat themselves in 20160 different ways.
Step-by-step explanation:
Arrangements of n elements:
The number of arrangements of n elements is given by the following formula:
In this question:
For the first seat, that is, the driver seat, 4 possible people can sit.
For the remaining 7 seats, the number of ways in which the people can sit is an arrangement of 7 elements. So
The people can seat themselves in 20160 different ways.
._ is the tenths place . Therefore the answer is 2.8
What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Remark
What this is telling you to do is put 3x + 3 in the question wherever there was an x to start with.
Solution
f(x) = -3x + 4
f(3x + 3) = - 3(3x + 3) + 4
f(3x + 3) = -3*3x + (-3)*(3) + 4
f(3x + 3) = - 9x - 9 + 4
f(3x + 3) = -9x - 5 <<<<< Answer
