We are given the function
F(x) = 9 sinx + cot x
We need to take the first derivative of the given function so,
F' (x) = 9 cos x - csc² x
Next, we equate the first derivative of the function to 0 and solve for the values of x
0 = 9 cos x - csc² x
Solving for x
x = 2.04
Picking out an arbitrary value between 2.04 and π, say 3 and substituting in F(x)
F(3) = 9 sin 3 + cot 3 = 19.55
Therefore, the interval where the function is increasing is from 2.04 to π
Consequently, the interval where the function is decreasing is from -π to 2.04<span />
The answer is 74.90.
I don't understand what you mean by 'Why it doesn't show'
Yes, because 3 1/3 times 45 equals 150 which leaves 10 cups left over:
Process: x^2 -12x +36 =0
(X-6) ^2 =0
X-6=0
Result: x=6
