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Diano4ka-milaya [45]
3 years ago
13

When you're listening to FM radio near buildings, reflections of the radio wave can make the reception particularly bad in certa

in locations. How can you compare this effect to the problem of uneven cooking in a microwave oven?
Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

Explained

Explanation:

The radio and the microwaves form a kind of destructive interference in the electromagnetic waves. This destructive interference leads to poor sound reception and uneven cooking. In order to avoid this radios, TVs should not be kept near the microwave ovens. This will avoid the occurrence of interference.

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Question 8 of 25
Dima020 [189]

Answer:

B.

Explanation:

8 0
3 years ago
Calculate the linear acceleration of a car, the 0.220-m radius tires of which have an angular acceleration of 13.0 rad/s2. Assum
Anuta_ua [19.1K]

Answer:

The linear acceleration of the car is 2.86m/s².

Explanation:

First of all, we have that the linear acceleration of the car and the tires is the same, because it moves ahead without disassembling itself. So, we only have to calculate the linear acceleration of the tires.

Next, it is known that the linear and angular acceleration are related by the formula:

a=\alpha R

Finally, we plug in the given values in order to calculate the acceleration:

a=(13.0rad/s^{2})(0.220m)=2.86m/s^{2}

It means that the linear acceleration of the car is 2.86m/s².

6 0
4 years ago
hich muscle fibers are best suited for activities that involve lifting large, heavy objects for a short period of time? cardiac
Temka [501]

Answer:

Dead lifting uses tho muscle fundamentals

Explanation:

6 0
4 years ago
A 5.0 kg wooden block is placed at an adjustable inclined plane. what is the angle of incline above which the block will start t
Aleks [24]
The value of the angle of the incline \theta at which the block starts to slide is the angle at which the component of the weight parallel to the incline becomes equal to the frictional force that keeps the block on the incline:
mg \sin \theta = \mu N
where the term on the left is the component of the weight parallel to the incline, and the term on the right is the frictional force, which is the product between the coefficient of friction \mu and the normal reaction of the incline N.

The normal reaction of the incline, N, is equal to the component of the weight perpendicular to the incline:
N=mg \cos \theta
Therefore, the initial equation becomes
mg \sin \theta = \mu mg \cos \theta
From which we find
\tan \theta = \mu
\theta = \arctan \mu

For angles above this value, the block will start sliding down, otherwise the block will stay on the incline.

3 0
3 years ago
Which movement causes day and night on Earth?
Brilliant_brown [7]

Answer:

The rotation of Earth

5 0
3 years ago
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