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Tasya [4]
3 years ago
14

Tell whether the picture below shows a

Physics
2 answers:
nlexa [21]3 years ago
7 0

Answer:

1. game

2. game

3. game

4. sports

5. sports

6. game

7. game

8. sports

hope it helps:)

san4es73 [151]3 years ago
5 0

Answer:

1. sports

2. game

3. game

4. sports

5. sports

6. sports

7. game

8. game

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A circular 10-turn coil with a radius of 5.0 cm carries a current of 5 A. It lies in the xy plane in a uniform magnetic field =
Tju [1.3M]

Answer:

U = – 0.12J

Explanation:

Given N = 10 turns, I = 5A, r = 5×10-²m

B^ = 0.05 T iˆ+ 0.3 T kˆ

Magnitude of the magnetic field vector B = √(0.05²+0.3²) = 0.304T

Area = πr² = π(5×10-²)² = 7.85×10-³m²

Magnetic moment μ = NIA

μ = 10×5×7.85×10-³ = 0.3925Am²

U = -μ•B = –0.3925×0.304 = –0.12J

The sign is negative because the magnetic moment is aligned with the magnetic field.

3 0
3 years ago
A hydrogen atom Is In Its ground state when Its orbital electron is what
cricket20 [7]

Answer: K-core , 1s orbital

Explanation:  Electron of Hydrogen atom has lowest energy

when it is in K core (1s-orbital)

8 0
3 years ago
LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.
Svetradugi [14.3K]

Answer:

i) E = 269 [MJ]    ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

i)

E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.

W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]

8 0
3 years ago
If the voltage is 120 v, and the desired current is 5 a, what resistance must be in the circuit?
ch4aika [34]
Resistance = (voltage) / (current)

= 24 ohms.
7 0
3 years ago
Is there a point between a 10 nc charge and a 20 nc charge at which the electric field is zero?
KonstantinChe [14]

Let 10 nC and 20 nC charge is placed at "d" distance

now let say we will have a point at distance "x" from 10 nC at which electric field will be zero

now we will have

E_1 = E_2

\frac{kq_1}{x^2} = \frac{kq_2}{(d-x)^2}

now plug in all data

\frac{k(10 nC)}{x^2} = \frac{k(20 nC)}{(d-x)^2}

\frac{10}{x^2} = \frac{20}{(d-x)^2}

square root both sides

\frac{1}{x} = \frac{\sqrt2}{d - x}

d - x = \sqrt2 x

d = x(1 + \sqrt2)

x = \frac{d}{1 + \sqrt2}

so yes there will exist a point between 10 nC and 20 nC charge at which electric field will be zero

3 0
3 years ago
Read 2 more answers
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